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#10274 Variant sorting should take into account that there might not be any language #10278

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merged 2 commits into from
May 18, 2021
Merged

#10274 Variant sorting should take into account that there might not be any language #10278

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Variant sorting should take into account that there might not be any …
nielslyngsoe May 17, 2021
9e6d3d6
fix languages
madsrasmussen May 18, 2021
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15 changes: 8 additions & 7 deletions src/Umbraco.Web.UI.Client/src/common/services/contenteditinghelper.service.js
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Original file line number Diff line number Diff line change
Expand Up @@ -789,10 +789,10 @@ function contentEditingHelper(fileManager, $q, $location, $routeParams, editorSt
*/
sortVariants: function (a, b) {
const statesOrder = {'PublishedPendingChanges':1, 'Published': 1, 'Draft': 2, 'NotCreated': 3};
const compareDefault = (a,b) => (!a.language.isDefault ? 1 : -1) - (!b.language.isDefault ? 1 : -1);
const compareDefault = (a,b) => (a.language && a.language.isDefault ? -1 : 1) - (b.language && b.language.isDefault ? -1 : 1);

// Make sure mandatory variants goes on top, unless they are published, cause then they already goes to the top and then we want to mix them with other published variants.
const compareMandatory = (a,b) => (a.state === 'PublishedPendingChanges' || a.state === 'Published') ? 0 : (!a.language.isMandatory ? 1 : -1) - (!b.language.isMandatory ? 1 : -1);
const compareMandatory = (a,b) => (a.state === 'PublishedPendingChanges' || a.state === 'Published') ? 0 : (a.language && a.language.isMandatory ? -1 : 1) - (b.language && b.language.isMandatory ? -1 : 1);
const compareState = (a, b) => (statesOrder[a.state] || 99) - (statesOrder[b.state] || 99);
const compareName = (a, b) => a.displayName.localeCompare(b.displayName);

Expand All @@ -813,17 +813,18 @@ function contentEditingHelper(fileManager, $q, $location, $routeParams, editorSt
*/
getSortedVariantsAndSegments: function (variantsAndSegments) {
const sortedVariants = variantsAndSegments.filter(variant => !variant.segment).sort(this.sortVariants);
let segments = variantsAndSegments.filter(variant => variant.segment);
let variantsWithSegments = variantsAndSegments.filter(variant => variant.segment);
let sortedAvailableVariants = [];

sortedVariants.forEach((variant) => {
const sortedMatchedSegments = segments.filter(segment => segment.language.culture === variant.language.culture).sort(this.sortVariants);
segments = segments.filter(segment => segment.language.culture !== variant.language.culture);
const sortedMatchedSegments = variantsWithSegments.filter(segment => segment.language && variant.language && segment.language.culture === variant.language.culture).sort(this.sortVariants);
// remove variants for this culture
variantsWithSegments = variantsWithSegments.filter(segment => !segment.language || segment.language && variant.language && segment.language.culture !== variant.language.culture);
sortedAvailableVariants = [...sortedAvailableVariants, ...[variant], ...sortedMatchedSegments];
})

// if we have segments without a parent language variant we need to add the remaining segments to the array
sortedAvailableVariants = [...sortedAvailableVariants, ...segments.sort(this.sortVariants)];
// if we have segments without a parent language variant we need to add the remaining variantsWithSegments to the array
sortedAvailableVariants = [...sortedAvailableVariants, ...variantsWithSegments.sort(this.sortVariants)];

return sortedAvailableVariants;
}
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