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#10274 Variant sorting should take into account that there might not …
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…be any language (#10278)

* Variant sorting should take into account that there might not be any language available

* fix languages

Co-authored-by: Niels Lyngsø <[email protected]>
Co-authored-by: Mads Rasmussen <[email protected]>
(cherry picked from commit e19a598)
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nielslyngsoe authored and nul800sebastiaan committed May 19, 2021
1 parent a3e3e83 commit 36c49b0
Showing 1 changed file with 8 additions and 7 deletions.
Original file line number Diff line number Diff line change
Expand Up @@ -775,10 +775,10 @@ function contentEditingHelper(fileManager, $q, $location, $routeParams, editorSt
*/
sortVariants: function (a, b) {
const statesOrder = {'PublishedPendingChanges':1, 'Published': 1, 'Draft': 2, 'NotCreated': 3};
const compareDefault = (a,b) => (!a.language.isDefault ? 1 : -1) - (!b.language.isDefault ? 1 : -1);
const compareDefault = (a,b) => (a.language && a.language.isDefault ? -1 : 1) - (b.language && b.language.isDefault ? -1 : 1);

// Make sure mandatory variants goes on top, unless they are published, cause then they already goes to the top and then we want to mix them with other published variants.
const compareMandatory = (a,b) => (a.state === 'PublishedPendingChanges' || a.state === 'Published') ? 0 : (!a.language.isMandatory ? 1 : -1) - (!b.language.isMandatory ? 1 : -1);
const compareMandatory = (a,b) => (a.state === 'PublishedPendingChanges' || a.state === 'Published') ? 0 : (a.language && a.language.isMandatory ? -1 : 1) - (b.language && b.language.isMandatory ? -1 : 1);
const compareState = (a, b) => (statesOrder[a.state] || 99) - (statesOrder[b.state] || 99);
const compareName = (a, b) => a.displayName.localeCompare(b.displayName);

Expand All @@ -799,17 +799,18 @@ function contentEditingHelper(fileManager, $q, $location, $routeParams, editorSt
*/
getSortedVariantsAndSegments: function (variantsAndSegments) {
const sortedVariants = variantsAndSegments.filter(variant => !variant.segment).sort(this.sortVariants);
let segments = variantsAndSegments.filter(variant => variant.segment);
let variantsWithSegments = variantsAndSegments.filter(variant => variant.segment);
let sortedAvailableVariants = [];

sortedVariants.forEach((variant) => {
const sortedMatchedSegments = segments.filter(segment => segment.language.culture === variant.language.culture).sort(this.sortVariants);
segments = segments.filter(segment => segment.language.culture !== variant.language.culture);
const sortedMatchedSegments = variantsWithSegments.filter(segment => segment.language && variant.language && segment.language.culture === variant.language.culture).sort(this.sortVariants);
// remove variants for this culture
variantsWithSegments = variantsWithSegments.filter(segment => !segment.language || segment.language && variant.language && segment.language.culture !== variant.language.culture);
sortedAvailableVariants = [...sortedAvailableVariants, ...[variant], ...sortedMatchedSegments];
})

// if we have segments without a parent language variant we need to add the remaining segments to the array
sortedAvailableVariants = [...sortedAvailableVariants, ...segments.sort(this.sortVariants)];
// if we have segments without a parent language variant we need to add the remaining variantsWithSegments to the array
sortedAvailableVariants = [...sortedAvailableVariants, ...variantsWithSegments.sort(this.sortVariants)];

return sortedAvailableVariants;
}
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