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Doubts about the size of the Hessian matrix #2544

Answered by jcarpent
Mr-Red331 asked this question in Q&A
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The kinematic Jacobian is the variation of a placement entity (position + orientation) with respect to the joint configuration vector.
Otherwise said, the kinematic Jacobian is the first-order derivative, reading $^0J_i = \frac{\partial ^0M_i(q)}{\partial q}$. The Jacobian evaluated at a given configuration value $q$ is a matrix of dimension $6 x \text{nv}$ where $\text{nv}$ is the size of the velocity vector (given by model.nv in Pinocchio), which can also be interpreted as the number of degrees of freedom.

The kinematic Hessian is one order of derivation more and corresponds to $^0H_i = \frac{{\partial^{2}} \ {^0M_i}(q)}{\partial q^2}$.
So, it is a $6 x \text{nv} x \text{nv}$ tensor, wi…

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@Mr-Red331
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Converted from issue

This discussion was converted from issue #2543 on January 04, 2025 08:39.