chore(find): simplify vnode traversal #835
Merged
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Basically, this is a proper finisher for #188 - we can avoid going over same vnodes again and again if we do not queue them multiple times - as long as we queue
node.component.subTree
- no need to queuesubTree.children
- they will be aggregated later by callingaggregateChildren(nodes, node.children)
@lmiller1990 I think you will be happy to see we're finally simplifying this part a bit :)