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Do not compare finished and all tasks sets eagerly #14635

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Oct 17, 2022
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Original file line number Diff line number Diff line change
Expand Up @@ -60,6 +60,7 @@
import java.util.stream.Stream;

import static com.google.common.base.Preconditions.checkArgument;
import static com.google.common.base.Preconditions.checkState;
import static com.google.common.collect.ImmutableList.toImmutableList;
import static com.google.common.collect.ImmutableSet.toImmutableSet;
import static io.airlift.http.client.HttpUriBuilder.uriBuilderFrom;
Expand Down Expand Up @@ -395,7 +396,11 @@ private synchronized boolean isStageFlushing()

private synchronized boolean isStageFinished()
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Can we do similar optimization in isStageFlushing ?

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@Dith3r Dith3r Oct 17, 2022

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isStageFlushing we check two different sets. There is a high chance that flushing size and finished size will be higher than allTask size (first we add to finished, and then we remove from flushing).

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Right, if we can have a task id in both sets at some point in time, then we can't make similar optimization there.

{
return finishedTasks.containsAll(allTasks);
boolean finished = finishedTasks.size() == allTasks.size();
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If we are 100% sure that finishedTasks will not contain any additional tasks which are not included in allTasks this is ok, but I would think of >= comparison here.

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If we are 100% sure that finishedTasks will not contain any additional tasks which are not included in allTasks

That would be a bug

if (finished) {
checkState(finishedTasks.containsAll(allTasks), "Finished tasks should contain all tasks");
}
return finished;
}

private boolean addFlushingTask(TaskId taskId)
Expand Down