Newline isn't escaped when backslash is not preceded by whitespace

[verhovsky]

echo a \
    b

parses correctly, however removing the space before the \

echo a\
    b

causes it to get parsed as a concatenation:

import Parser from 'web-tree-sitter';

await Parser.init();
const Bash = await Parser.Language.load('./tree-sitter-bash.wasm');
const parser = new Parser();
parser.setLanguage(Bash);

const result = parser.parse("echo a \\\n    b");
console.log(result.rootNode.toString())
console.log(result.rootNode.firstChild.children.map(x => x.text));

const badresult = parser.parse("echo a\\\n    b");
console.log(badresult.rootNode.toString())
console.log(badresult.rootNode.firstChild.children.map(x => x.text));

Output:

(program (command name: (command_name (word)) argument: (word) argument: (word)))
[ 'echo', 'a', 'b' ]
(program (command name: (command_name (word)) argument: (concatenation (word) (word))))
[ 'echo', 'a\\\n    b' ]

You can see that this doesn't happen on my GNU bash, version 5.1.8(1)-release (aarch64-apple-darwin20.4.0):

 $ echo a \
>   b
a b
$ echo a\
>   b
a b

there are multiple spaces before "b", but because bash parses them as two separate arguments, echo prints them separated by only 1 space, as expected.

[verhovsky]

@maxbrunsfeld

We just had a user open an issue about this.

[verhovsky]

@maxbrunsfeld if you find a chance to do it, can I get a release please?