github: deal with directory links correctly in file_info()
#134
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Getting the contents of a directory from the API returns a list, not a dict, so calling `.get()` on the resulting data fails. Instead, make sure the data parsed to a Mapping first, *then* check if the 'type' within the JSON response was 'file' or not.
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Getting the contents of a directory from the API returns a list, not a dict, so calling
.get()on the resulting data fails.Instead, make sure the data parsed to a Mapping first, then check if the 'type' within the JSON response was 'file' or not.