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plot_pairwise_average_fst may change the order of the cohorts when using a cohort dict #540
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6cae710
Changed the unique function used to avoid sorting
jonbrenas 8e9037a
Merge branch 'master' into 539-no-alphabeticl-sorting-of-keys-fst-plots
alimanfoo eeaa693
Merge branch 'master' into 539-no-alphabeticl-sorting-of-keys-fst-plots
jonbrenas bbb31a5
Merge branch 'master' into 539-no-alphabeticl-sorting-of-keys-fst-plots
leehart 3622b97
A line was missing and used flatten.
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The for loops in this line look a little funky. What is it supposed to be doing?
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The goal is to get the list of all cohorts in the same order they were defined in the cohort dictionary.
plot_pairwise_average_fst
does not have the list of cohorts or the dictionary as an input so we have to access it in another way.fst_df[["cohort1", "cohort2"]]
is a list of list each one containing two cohort names. The last cohort of the dictionary is missing from thecohort1
column and the first is missing fromcohort2
, hence why they are both accessed.np.unique
is able to take a list of list and return every unique value but it sorts them alphabetically breaking the dictionary's order.pd.unique
keeps the order but can't deal with a list of lists. The for loops are thus used to go from a list of list of cohorts to a list of cohorts.There was a problem hiding this comment.
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Thanks @jonbrenas. What about:
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Nested list comprehensions always bake my noodle!
I think it's equivalent to this:
Or like Alistair suggested: