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[11.x] Applying value Function into the $default value of transform helper #52510

Merged
merged 1 commit into from
Aug 19, 2024
Merged

[11.x] Applying value Function into the $default value of transform helper #52510

merged 1 commit into from
Aug 19, 2024

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devajmeireles
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The $default value of the transform function does not pass through the value to allow the execution of a closure to obtain the default value, for example. This PR fixes this by passing $default through the value helper.

@taylorotwell
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Would this be considered a breaking change?

@devajmeireles
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Would this be considered a breaking change?

I strongly believe not, since both value and transform set $default in the same way.

@rodrigopedra
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rodrigopedra commented Aug 18, 2024

Only if someone is expecting the $default to be a callable, then instead of getting it, they would get the result of its execution.

Which, IMO, is highly unlikely.

@taylorotwell taylorotwell merged commit 29e8040 into laravel:11.x Aug 19, 2024
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@rodrigopedra
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@taylorotwell actually this is unneeded, re-reading my comment, I fell I oversaw it. The transform helper already checks if the $default is a callable, and if so calls it with the $value as a parameter:

function transform($value, callable $callback, $default = null)
{
if (filled($value)) {
return $callback($value);
}
if (is_callable($default)) {
return $default($value);
}
return value($default);
}

The line modified in this PR only adds a function call to the stack call, as $default never be a callable at this point:

// $default is never a callable here
return value($default);

Other than the useless function call, there is no harm in keeping it, so I didn't send a PR to revert it.

@devajmeireles
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@taylorotwell actually this is unneeded, re-reading my comment, I fell I oversaw it. The transform helper already checks if the $default is a callable, and if so calls it with the $value as a parameter:

function transform($value, callable $callback, $default = null)
{
if (filled($value)) {
return $callback($value);
}
if (is_callable($default)) {
return $default($value);
}
return value($default);
}

The line modified in this PR only adds a function call to the stack call, as $default never be a callable at this point:

// $default is never a callable here
return value($default);

Other than the useless function call, there is no harm in keeping it, so I didn't send a PR to revert it.

We're not just talking about callables.

@rodrigopedra
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Just to be clear, you did check the value() implementation, right?

function value($value, ...$args)
{
return $value instanceof Closure ? $value(...$args) : $value;
}

If the $value argument isn't a \Closure, this helper just returns the $value variable.

As the if clause just before the modified line excludes the possibility of $value being a callable, the line modified in this PR adds no value, and worst, just adds a function call.

We're not just talking about callables.

Now you let me curious, I guess we mutually agree that in the modified line, $value will never be a callable, and thus never be a \Closure, which excludes the \Closure path from the value() ternary implementation, right?

So, what are you talking about, then?

@devajmeireles devajmeireles deleted the applying-value-in-transform-default branch August 20, 2024 03:07
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3 participants