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comparison using is/is not with string literal rasises SyntaxWarning #185
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https://github.com/kennethreitz-archive/clint/blob/9d3693d644b8587d985972b6075d970096f6439e/clint/textui/prompt.py#L69
This line uses 'is not' to compare variable with string literal. This should be '=' and in python 3.8 and later raises following warning.
SyntaxWarning: "is not" with a literal. Did you mean "!="?
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