Revert "Merge pull request #1399 from aweary/use-react-reconciler-rea…

…ct-16"

This reverts commit d60360c, reversing
changes made to bbf39e0.

packages/enzyme-adapter-react-16/package.json

@@ -40,7 +40,6 @@
     "object.values": "^1.0.4",
     "prop-types": "^15.6.2",
     "react-is": "^16.4.2",
-    "react-reconciler": "^0.7.0",
     "react-test-renderer": "^16.0.0-0"
   },
   "peerDependencies": {

packages/enzyme-adapter-react-16/src/ReactSixteenAdapter.js

@@ -36,7 +36,7 @@ import {
   propsWithKeysAndRef,
   ensureKeyOrUndefined,
 } from 'enzyme-adapter-utils';
-import { findCurrentFiberUsingSlowPath } from 'react-reconciler/reflection';
+import findCurrentFiberUsingSlowPath from './findCurrentFiberUsingSlowPath';
 
 const HostRoot = 3;
 const ClassComponent = 2;

packages/enzyme-adapter-react-16/src/findCurrentFiberUsingSlowPath.js

@@ -0,0 +1,104 @@
+// Extracted from https://github.com/facebook/react/blob/7bdf93b17a35a5d8fcf0ceae0bf48ed5e6b16688/src/renderers/shared/fiber/ReactFiberTreeReflection.js#L104-L228
+function findCurrentFiberUsingSlowPath(fiber) {
+  const { alternate } = fiber;
+  if (!alternate) {
+    return fiber;
+  }
+  // If we have two possible branches, we'll walk backwards up to the root
+  // to see what path the root points to. On the way we may hit one of the
+  // special cases and we'll deal with them.
+  let a = fiber;
+  let b = alternate;
+  while (true) { // eslint-disable-line
+    const parentA = a.return;
+    const parentB = parentA ? parentA.alternate : null;
+    if (!parentA || !parentB) {
+      // We're at the root.
+      break;
+    }
+
+    // If both copies of the parent fiber point to the same child, we can
+    // assume that the child is current. This happens when we bailout on low
+    // priority: the bailed out fiber's child reuses the current child.
+    if (parentA.child === parentB.child) {
+      let { child } = parentA;
+      while (child) {
+        if (child === a) {
+          // We've determined that A is the current branch.
+          return fiber;
+        }
+        if (child === b) {
+          // We've determined that B is the current branch.
+          return alternate;
+        }
+        child = child.sibling;
+      }
+      // We should never have an alternate for any mounting node. So the only
+      // way this could possibly happen is if this was unmounted, if at all.
+      throw new Error('Unable to find node on an unmounted component.');
+    }
+
+    if (a.return !== b.return) {
+      // The return pointer of A and the return pointer of B point to different
+      // fibers. We assume that return pointers never criss-cross, so A must
+      // belong to the child set of A.return, and B must belong to the child
+      // set of B.return.
+      a = parentA;
+      b = parentB;
+    } else {
+      // The return pointers point to the same fiber. We'll have to use the
+      // default, slow path: scan the child sets of each parent alternate to see
+      // which child belongs to which set.
+      //
+      // Search parent A's child set
+      let didFindChild = false;
+      let { child } = parentA;
+      while (child) {
+        if (child === a) {
+          didFindChild = true;
+          a = parentA;
+          b = parentB;
+          break;
+        }
+        if (child === b) {
+          didFindChild = true;
+          b = parentA;
+          a = parentB;
+          break;
+        }
+        child = child.sibling;
+      }
+      if (!didFindChild) {
+        // Search parent B's child set
+        ({ child } = parentB);
+        while (child) {
+          if (child === a) {
+            didFindChild = true;
+            a = parentB;
+            b = parentA;
+            break;
+          }
+          if (child === b) {
+            didFindChild = true;
+            b = parentB;
+            a = parentA;
+            break;
+          }
+          child = child.sibling;
+        }
+        if (!didFindChild) {
+          throw new Error('Child was not found in either parent set. This indicates a bug '
+            + 'in React related to the return pointer. Please file an issue.');
+        }
+      }
+    }
+  }
+  if (a.stateNode.current === a) {
+    // We've determined that A is the current branch.
+    return fiber;
+  }
+  // Otherwise B has to be current branch.
+  return alternate;
+}
+
+module.exports = findCurrentFiberUsingSlowPath;