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Consistent action of conjugation #26
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switzel
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According to Transform.apply_to_tuple() a potential conjugation is first applied before the matrix is multiplied. Since the action is from the left this means that conjugation is on the right. Thus in Transform.merge() conjugation has to be applied to the entries of the product of the factors to the right not to the left. This commit fixes this.
VascoSch92
reviewed
Feb 22, 2024
@@ -95,13 +95,13 @@ def identity(): | |||
def merge(*transfoms): | |||
a,b,c,d = 1,0,0,1 | |||
conj = False | |||
for i, trans in enumerate(transfoms): | |||
for trans in reversed(transfoms): | |||
a2,b2,c2,d2 = trans.abcd | |||
if trans.conj: | |||
a,b,c,d = (a.conjugate(), b.conjugate(), c.conjugate(), |
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you don't need the ( and ) here
VascoSch92
reviewed
Feb 22, 2024
a2,b2,c2,d2 = trans.abcd | ||
if trans.conj: | ||
a,b,c,d = (a.conjugate(), b.conjugate(), c.conjugate(), | ||
d.conjugate()) | ||
conj = not conj | ||
a,b,c,d = a*a2+c*b2, b*a2+d*b2, a*c2+c*d2, b*c2+d*d2 | ||
a,b,c,d = a2*a+b2*c, a2*b+b2*d, c2*a+d2*c, c2*b+d2*d | ||
return Transform(a,b,c,d,conj=conj) | ||
@staticmethod |
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leave a space between two methods
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It should generally be true that
a.apply_to_point(b.apply_to_point(p)) == Transform.merge(a,b).apply_to_point(p)
(up to numerical error).
According to Transform.apply_to_tuple() a potential conjugation is first applied before the matrix is multiplied. Since the action is from the left this means that conjugation is on the right.
Thus in Transform.merge() conjugation has to be applied to the entries of the product of the factors to the right not to the left (see issue #24). This commit fixes this.