MNT #303 use a symbol

hkl/tests/test_diffract.py

@@ -368,21 +368,22 @@ def test_i303_forward_solution_original_problem(e4cv):
 
     e4cv.calc.engine.mode = "constant_phi"
     assert e4cv.calc.engine.mode == "constant_phi"
+    CONSTANT_PHI = 23.4567
 
-    e4cv.apply_constraints({"phi": Constraint(-180, 180, 21.3456, True)})
-    assert pytest.approx(e4cv.calc["phi"].value, abs=1e-4) == 21.3456
+    e4cv.apply_constraints({"phi": Constraint(-180, 180, CONSTANT_PHI, True)})
+    assert pytest.approx(e4cv.calc["phi"].value, abs=1e-4) == CONSTANT_PHI
 
     # Check that phi is held constant in forward_solutions_table()
     # Returns a pyRestTable.Table object.
     table = e4cv.forward_solutions_table([refl], full=True, digits=4)
     assert len(table.rows) == 2
     assert table.labels[4] == "phi"
-    assert pytest.approx(table.rows[0][4], abs=1e-4) == 21.3456
-    assert pytest.approx(table.rows[1][4], abs=1e-4) == 21.3456
+    assert pytest.approx(table.rows[0][4], abs=1e-4) == CONSTANT_PHI
+    assert pytest.approx(table.rows[1][4], abs=1e-4) == CONSTANT_PHI
 
     # Check that phi is held constant in forward()
     # Returns a position namedtuple.
     position = e4cv.forward(refl)
-    assert pytest.approx(position.phi, abs=1e-4) == 21.3456
+    assert pytest.approx(position.phi, abs=1e-4) == CONSTANT_PHI
 
     e4cv.reset_constraints()