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Bulldog initializes PIN value with Signal.Low despite it's current value #47

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sbunciak opened this issue Aug 9, 2015 · 1 comment
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sbunciak commented Aug 9, 2015

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@sbunciak sbunciak added this to the 0.2.1 milestone Aug 9, 2015
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sbunciak commented Aug 9, 2015

E.g. assuming that PIN P1_11 has been set to high outside of Bulldog, the following will fail:

Board board = Platform.createBoard();
DigitalOutput outputPin = board.getPin("P1_11").as(DigitalOutput.class);

assertEquals(outputPin.getAppliedSignal(), Signal.High);

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