updated the vtable note

CPP/28.2-virtual-tables.md

@@ -10,29 +10,24 @@ Let's consider the following example:
 
 ```cpp
 class Base {
-public:
-    virtual void function1() {
-        std::cout << "Base::function1" << std::endl;
-    }
+  public:
+    virtual void function1() { std::cout << "Base::function1" << std::endl; }
 
-    virtual void function2() {
-        std::cout << "Base::function2" << std::endl;
-    }
+    virtual void function2() { std::cout << "Base::function2" << std::endl; }
 };
 
 class Derived : public Base {
-public:
+  public:
     void function1() override {
         std::cout << "Derived::function1" << std::endl;
     }
 
-    void function3() {
-        std::cout << "Derived::function3" << std::endl;
-    }
+    void function3() { std::cout << "Derived::function3" << std::endl; }
 };
 
 int main() {
-    Base* obj = new Derived(); // create a Derived object and assign a pointer of type Base*
+    Base* obj = new Derived(); // create a Derived object and assign a pointer
+                               // of type Base*
     obj->function1(); // calls Derived::function1, due to dynamic polymorphism
     obj->function2(); // calls Base::function2
 
@@ -49,3 +44,7 @@ In this example, when a `Derived` object is created, the compiler generates a Vt
 The `_vptr_` pointer in the `Derived` object points to this Vtable. When the `function1` is called on the `Base` pointer pointing to the `Derived` object, the function pointer in the Vtable is used to call the correct function (in this case, `Derived::function1`). Similarly, the call to `function2` calls `Base::function2`, since it's the function pointer stored in the Vtable for `Derived` class.
 
 Note that `function3` is not part of the Vtable, as it is not a virtual function.
+
+## Diagram explanation
+
+![image](https://github.com/Rishabh672003/Programming-Notes/assets/53911515/dfc6208d-810e-4f51-9997-5473c1fb7f3f)