🐛(ozi.scripts.render_requirements): correct filtering of empty lines

Signed-off-by: rjdbcm <[email protected]>

ozi/scripts/render_requirements.py

@@ -26,7 +26,7 @@
     requirements = (
         r.partition('\u0023')[0]
         for r in filter(
-            lambda r: not (r.startswith('\u0023') or r == '\n'),
+            lambda r: not (r.startswith('\u0023') or r == ''),
             pathlib.Path('./requirements.in').read_text('utf-8').splitlines(),
         )
     )