Bernoulli should produce Bool

[MikeInnes]

I'm not clear why this changed in #1048 (apparently because Int may be easier to represent on quantum processors than Bool, which is not in fact the case.) I agree that it's good to be consistent, but it seems pretty clear that Bool is the right type to use here.

It's good to use the narrowest type available to represent an output, because (a) it gives useful information to tools and (b) narrow types can always be upcasted (to Int, Float etc.) but can't automatically be downcasted back to Bool, which means more code is convenient to write.

To come at it from the other direction – why use Int64 here but not Float64? Or BigInt? Or arbitrary-precision floating point?

[mschauer]

I think it is simple: it should be Bool so it works in conditionals.

[matbesancon]

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