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In Julia v0.6, I could do:
indmin(i for i=1:10000)
In Julia v0.7, this doesn't work:
argmin(i for i=1:10000)
Can you please add a lazy version again?
The text was updated successfully, but these errors were encountered:
Workaround Julia issue JuliaLang/julia#28349
48cdaf9
See #27612 and #27613.
Sorry, something went wrong.
Thank you, so it is already in your radar, I will close this one.
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In Julia v0.6, I could do:
In Julia v0.7, this doesn't work:
Can you please add a lazy version again?
The text was updated successfully, but these errors were encountered: