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Time - Yolotzin #29
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Time - Yolotzin #29
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# Time Complexity: ? | ||
# Space Complexity: ? | ||
# Time Complexity: O(n) | ||
# Space Complexity: O(1) | ||
def max_sub_array(nums) | ||
return 0 if nums == nil | ||
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raise NotImplementedError, "Method not implemented yet!" | ||
return nil if nums == nil || nums.empty? | ||
return nums[0] if nums.length == 1 | ||
max = nums[0] # start with first element and then skip in loop | ||
current = nums[0] | ||
i = 1 | ||
while i < nums.length | ||
current += nums[i] | ||
if max < current | ||
max = current | ||
end | ||
if current < 0 | ||
current = 0 | ||
end | ||
i += 1 | ||
end | ||
return max | ||
end | ||
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# Write a method to find the contiguous subarray in a 1-dimensional array with the largest sum. | ||
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# This can be solved using Kadane's Algorithm | ||
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# Initialize: | ||
# max_so_far = 0 | ||
# max_ending_here = 0 | ||
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# Loop for each element of the array | ||
# (a) max_ending_here = max_ending_here + a[i] | ||
# (b) if(max_ending_here < 0) | ||
# max_ending_here = 0 | ||
# (c) if(max_so_far < max_ending_here) | ||
# max_so_far = max_ending_here | ||
# return max_so_far | ||
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# The idea of the Kadane’s algorithm is to look for all positive contiguous segments of the array (max_ending_here is used for this). | ||
# And keep track of the maximum sum contiguous segment among all positive segments (max_so_far is used for this). | ||
# Each time we get a positive sum compare it with max_so_far and update max_so_far if it is greater than max_so_far | ||
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# There is also a subtle divide & conquer algorithm for this. |
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# Time complexity: ? | ||
# Space Complexity: ? | ||
# Time complexity: O(n) | ||
# Space Complexity: O(n) | ||
def newman_conway(num) | ||
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raise NotImplementedError, "newman_conway isn't implemented" | ||
end | ||
raise ArgumentError, 'must be number > 0' if num == 0 | ||
return "1" if num == 1 | ||
array = Array.new(num) | ||
array[0] = 0 | ||
array[1] = 1 | ||
array[2] = 1 | ||
i = 3 | ||
while i <= num | ||
array[i] = array[array[i - 1]] + array[i - array[i - 1]] | ||
i += 1 | ||
end | ||
return array[1..num].join(' ') | ||
end | ||
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# [Newman-Conway sequence] is the one which generates the following integer sequence. | ||
# 1 1 2 2 3 4 4 4 5 6 7 7….. | ||
# and follows below recursive formula. | ||
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# P(1) = 1 | ||
# P(2) = 1 | ||
# for all n > 2 | ||
# P(n) = P(P(n - 1)) + P(n - P(n - 1)) | ||
# Given a number n then print n terms of Newman-Conway Sequence | ||
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# Examples: | ||
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# Input : 13 | ||
# Output : 1 1 2 2 3 4 4 4 5 6 7 7 8 | ||
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# Input : 20 | ||
# Output : 1 1 2 2 3 4 4 4 5 6 7 7 8 8 8 8 9 10 11 12 | ||
# You should be able to do this in O(n) time complexity. | ||
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