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paidui.html
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<!DOCTYPE html>
<html lang="zh-cmn-Hans">
<head>
<meta charset='utf-8'>
<meta http-equiv="X-UA-Compatible" content="IE=edge,chrome=1"/>
<meta name="viewport" content="initial-scale=1, maximum-scale=3, minimum-scale=1, user-scalable=no">
<meta name="renderer" content="webkit">
<!-- 避免IE使用兼容模式 -->
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<!-- 针对手持设备优化，主要是针对一些老的不识别viewport的浏览器，比如黑莓 -->
<meta name="HandheldFriendly" content="true">
<!-- 微软的老式浏览器 -->
<meta name="MobileOptimized" content="320">
<!-- uc强制竖屏 -->
<meta name="screen-orientation" content="portrait">
<!-- QQ强制竖屏 -->
<meta name="x5-orientation" content="portrait">
<!-- UC强制全屏 -->
<meta name="full-screen" content="yes">
<!-- QQ强制全屏 -->
<meta name="x5-fullscreen" content="true">
<!-- UC应用模式 -->
<meta name="browsermode" content="application">
<!-- QQ应用模式 -->
<meta name="x5-page-mode" content="app">
<title>排队问题</title>
<style type="text/css">
tr:hover{background-color:#DDECF3;} /* 通过CSS实现鼠标悬停高亮色 */
.contentTitle{
background-color:beige;padding:15px;font-size:18px;
}
.contentRow{
padding:5px;font-family:Courier;font-size:20px;letter-spacing:5px;text-indent:20px;display: inline-block;vertical-align:middle;
}
td{
height: 51px;
}
</style>
<script type="text/javascript">
function g(m,n,k,type){
var _qianTxt="甲、乙二人排在一个队伍里。从前往后数甲排第m。".replace("m",m);
var _houTxt="从后往前数乙排第n。".replace("n",n);
var _jianGeTxt="甲、乙之间间隔k人。".replace("k",k);
var _typeTxt="甲在乙前。";
var _qTxt="问排队的总人数是多少人？";
var _answer="";
var _q="";
if (type==1) {
_typeTxt="甲在乙前。";
_q=_qianTxt+_houTxt+_typeTxt+_jianGeTxt+_qTxt;
_answer=m.toString()+"+"+n.toString()+"+"+k.toString();
_answer=_answer+"="+eval(_answer);
}else if (type==2){
_typeTxt="乙在甲前。";
_q=_qianTxt+_houTxt+_typeTxt+_jianGeTxt+_qTxt;
_answer=m.toString()+"+"+n.toString()+"-("+k.toString()+"+1+1)";
_answer=_answer+"="+eval(_answer)+"(人)";
}else if (type==3) {
_typeTxt="乙在甲前。";
_qTxt="甲乙之间最多间隔几人？";
_q=_qianTxt+_houTxt+_typeTxt+_qTxt;
_answer=eval(m.toString()+"<"+n.toString()
+"?"+m.toString()+":"
+n.toString())+"-1-1";
_answer=_answer+"="+eval(_answer);
};
return {
qu:_q,
ans:_answer
};
};
function getRed(m,n){
return Math.floor(Math.random()*(m-n+1)+n);
};
function createRow(que,i){
addNewTr("<div class='contentTitle' >"+"第 "+i+" 题"+"</div>");
addNewTr("<div class='contentRow' >"+que.qu+"</div>");
addNewTr("<div class='contentRow' style='display:none' ondblclick='JavaScript:this.style.display=\"\";'>"+que.ans+"</div>");
addNewTr("");
}
function check(rowId,answerA,answerB){
var answerAVal = document.getElementById("A"+rowId).value;
var answerBVal = document.getElementById("B"+rowId).value;
if (answerA==answerAVal && answerB==answerBVal) {
document.getElementById("mark"+rowId).innerHTML="<span style='color:green;font-size:14px'> √ 恭喜你回答正确！</span>"
+changeLevel("http://zxs731.github.io/index3_2.html","升一级");
}else{
document.getElementById("mark"+rowId).innerHTML="<span style='color:red;font-size:14px'> X 错误，再试一次吧！</span>"
+changeLevel("http://zxs731.github.io/index3_1.html","简单点");
}
}
function changeLevel(url,level){
return "<a href='"+url+"' style='color:green;font-size:14px'>"+level+"</a>";
};
function addNewTr(str){
var editTable=document.getElementById("tbody");
var tr4=document.createElement("tr");
var td4=document.createElement("td");
td4.innerHTML=str;
tr4.appendChild(td4);
editTable.appendChild(tr4);
}
function loadQuo(){
var s="";
for(var i=1;i<11;i++){
var s=getRed(0,4);
var it=g(getRed(5,20),getRed(5,20)
,getRed(2,5),s);
createRow(it,i);
}
console.log(s);
}
function getPicDiv(str){
var numx = getRandomInt(0, 10)*40;
var numy = getRandomInt(0, 10)*40;
var bordercolor="deepskyblue";
if (str=="A")
bordercolor="darkorange";
else if (str=="C") {
bordercolor="red";
};
var div ='<div style="display: inline-block;background: transparent url(2.jpg) no-repeat scroll -'+numx+'px -'+numy+'px;height: 40px;width: 40px;border-radius: 30px;vertical-align: middle;border-style:outset;border-color:'+bordercolor+'"></div>';
return div;
}
function getABCPics(){
var picA=getPicDiv('A');
var picB=getPicDiv('B');
var picC=getPicDiv('C');
while (picA==picB || picA==picC || picB==picC) {
picA=getPicDiv();
picB=getPicDiv();
picC=getPicDiv();
};
return {"A":picA,"B":picB,"C":picC};
}
</script>
</head>
<body onload="loadQuo();">
<table id="editTable" width="100%" border="1" cellpadding="0" cellspacing="0" bordercolor="gray" style="border-collapse:collapse;">
<tr>
<th><div style='padding:5px;font-size: 18px'>排队问题</div></th>
</tr>
<tbody id="tbody">
</tbody>
</table>
</body>
</html>