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1835. Find XOR Sum of All Pairs Bitwise AND

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Description

The XOR sum of a list is the bitwise XOR of all its elements. If the list only contains one element, then its XOR sum will be equal to this element.

• For example, the XOR sum of [1,2,3,4] is equal to 1 XOR 2 XOR 3 XOR 4 = 4, and the XOR sum of [3] is equal to 3.

You are given two 0-indexed arrays arr1 and arr2 that consist only of non-negative integers.

Consider the list containing the result of arr1[i] AND arr2[j] (bitwise AND) for every (i, j) pair where 0 <= i < arr1.length and 0 <= j < arr2.length.

Return the XOR sum of the aforementioned list.

 

Example 1:

Input: arr1 = [1,2,3], arr2 = [6,5]
Output: 0
Explanation: The list = [1 AND 6, 1 AND 5, 2 AND 6, 2 AND 5, 3 AND 6, 3 AND 5] = [0,1,2,0,2,1].
The XOR sum = 0 XOR 1 XOR 2 XOR 0 XOR 2 XOR 1 = 0.

Example 2:

Input: arr1 = [12], arr2 = [4]
Output: 4
Explanation: The list = [12 AND 4] = [4]. The XOR sum = 4.

 

Constraints:

• 1 <= arr1.length, arr2.length <= 105
• 0 <= arr1[i], arr2[j] <= 109

Solutions

Python3

class Solution:
    def getXORSum(self, arr1: List[int], arr2: List[int]) -> int:
        a = reduce(xor, arr1)
        b = reduce(xor, arr2)
        return a & b

Java

class Solution {
    public int getXORSum(int[] arr1, int[] arr2) {
        int a = 0, b = 0;
        for (int v : arr1) {
            a ^= v;
        }
        for (int v : arr2) {
            b ^= v;
        }
        return a & b;
    }
}

C++

class Solution {
public:
    int getXORSum(vector<int>& arr1, vector<int>& arr2) {
        int a = accumulate(arr1.begin(), arr1.end(), 0, bit_xor<int>());
        int b = accumulate(arr2.begin(), arr2.end(), 0, bit_xor<int>());
        return a & b;
    }
};

Go

func getXORSum(arr1 []int, arr2 []int) int {
	var a, b int
	for _, v := range arr1 {
		a ^= v
	}
	for _, v := range arr2 {
		b ^= v
	}
	return a & b
}

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