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Difficulty: 中等
Related Topics: 树, 深度优先搜索, 广度优先搜索, 二叉树
给定一个二叉树的 根节点 root,想象自己站在它的右侧,按照从顶部到底部的顺序,返回从右侧所能看到的节点值。
root
示例 1:
输入: [1,2,3,null,5,null,4] 输出: [1,3,4]
示例 2:
输入: [1,null,3] 输出: [1,3]
示例 3:
输入: [] 输出: []
提示:
[0,100]
-100 <= Node.val <= 100
Language: JavaScript
/** * Definition for a binary tree node. * function TreeNode(val, left, right) { * this.val = (val===undefined ? 0 : val) * this.left = (left===undefined ? null : left) * this.right = (right===undefined ? null : right) * } */ /** * @param {TreeNode} root * @return {number[]} */ // var rightSideView = function(root) { // const res = [] // const dfs = (root, depth) => { // if (!root) return null // if (depth === res.length) { // res.push(root.val) // } // depth++ // dfs(root.right, depth) // dfs(root.left, depth) // } // dfs(root, 0) // return res // }; var rightSideView = function(root) { if (!root) return [] const q = [root] const res = [] while (q.length) { let len = q.length while(len--) { const n = q.shift() if (!len) res.push(n.val) n.left && q.push(n.left) n.right && q.push(n.right) } } return res }
The text was updated successfully, but these errors were encountered:
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199. 二叉树的右视图
Description
Difficulty: 中等
Related Topics: 树, 深度优先搜索, 广度优先搜索, 二叉树
给定一个二叉树的 根节点
root
,想象自己站在它的右侧,按照从顶部到底部的顺序,返回从右侧所能看到的节点值。示例 1:
示例 2:
示例 3:
提示:
[0,100]
-100 <= Node.val <= 100
Solution
Language: JavaScript
The text was updated successfully, but these errors were encountered: