| layout | title | <!---description |
|---|---|---|
default |
Thrust - Parallel Algorithms Library |
TODO Index Description--> |
Thrust is a parallel algorithms library which resembles the C++ Standard Template Library (STL). Thrust's high-level interface greatly enhances programmer productivity while enabling performance portability between GPUs and multicore CPUs. Interoperability with established technologies (such as CUDA, TBB, and OpenMP) facilitates integration with existing software. Develop high-performance applications rapidly with Thrust!
Thrust is best explained through examples. The following source code generates random numbers serially and then transfers them to a parallel device where they are sorted.
{% highlight c++ %} #include <thrust/host_vector.h> #include <thrust/device_vector.h> #include <thrust/generate.h> #include <thrust/sort.h> #include <thrust/copy.h> #include #include
int main(void) { // generate 32M random numbers serially thrust::host_vector h_vec(32 << 20); std::generate(h_vec.begin(), h_vec.end(), rand);
// transfer data to the device thrust::device_vector d_vec = h_vec;
// sort data on the device (846M keys per second on GeForce GTX 480) thrust::sort(d_vec.begin(), d_vec.end());
// transfer data back to host thrust::copy(d_vec.begin(), d_vec.end(), h_vec.begin());
return 0; } {% endhighlight %}
This code sample computes the sum of 100 random numbers in parallel:
{% highlight c++ %} #include <thrust/host_vector.h> #include <thrust/device_vector.h> #include <thrust/generate.h> #include <thrust/reduce.h> #include <thrust/functional.h> #include #include
int main(void) { // generate random data serially thrust::host_vector h_vec(100); std::generate(h_vec.begin(), h_vec.end(), rand);
// transfer to device and compute sum thrust::device_vector d_vec = h_vec; int x = thrust::reduce(d_vec.begin(), d_vec.end(), 0, thrust::plus()); return 0; } {% endhighlight %}
Refer to the Quick Start Guide page for further information and examples.
The original creators of Thrust are Jared Hoberock and Nathan Bell.