source prolog file not working

[nikoladze]

Hi,

When i pass a file by the --prolog argument i get the error message:

OSError: [Errno 2] No such file or directory

originating from the subprocess.Popen call in:

scoop/scoop/launch/workerLaunch.py

Lines 192 to 195 in d391dfa

	if self.isLocal():
	# Launching local workers
	c = self._getWorkerCommandList()
	self.subprocesses.append(subprocess.Popen(c))

The error seems to refer to the bash builtin source. When i run the above command with shell=True and executable="/bin/bash" it seems to work

self.subprocesses.append(subprocess.Popen(" ".join(c), shell=True, executable="/bin/bash"))

I'm aware this poses security risks and i have no overview which (potentially un-escaped) external inputs go into this command, so i'm not suggesting to just fix it in this way. Also i don't know if relying on bash is the only way to do this.
Maybe somebody has an idea?

Cheers,
Nikolai

[ljluestc]

import subprocess
import shlex

Construct the subprocess command

prolog_command = [
'/full/path/to/your/prolog_script.sh',
'arg1',
'arg2',
]

Escape and join the command arguments

escaped_command = ' '.join(shlex.quote(arg) for arg in prolog_command)

Run the subprocess

subprocess.Popen(escaped_command, shell=True, executable="/bin/bash")