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math #5

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silverwind opened this issue Sep 1, 2022 · 4 comments
Open

math #5

silverwind opened this issue Sep 1, 2022 · 4 comments

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@silverwind
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silverwind commented Sep 1, 2022

Here is some math!

$$\sqrt{3}$$
@silverwind
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When $a \ne 0$, there are two solutions to $(ax^2 + bx + c = 0)$ and they are
$$ x = {-b \pm \sqrt{b^2-4ac} \over 2a} $$

@zeripath
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zeripath commented Sep 4, 2022

$$Does it need $\sqrt{3}$ ?$$ $$ x = {-b \pm \sqrt{b^2-4ac} \over 2a} $$ $$\[ x = {-b \pm \sqrt{b^2-4ac} \over 2a} \]$$

@zeripath
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zeripath commented Sep 4, 2022

yup looks like fenced blocks don't work

@silverwind
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silverwind commented Mar 29, 2024

$x$ -$x$ $x$-

a$xa$ $xa$a 1$xb$ $xb$1

$a a$b b$

a$b $a a$b b$

$a a$b b$


aa

$$\left( \sum_{k=1}^n a_k b_k \right)^2 \leq \left( \sum_{k=1}^n a_k^2 \right) \left( \sum_{k=1}^n b_k^2 \right)$$

This sentence uses $ delimiters to show math inline: $\sqrt{3x-1}+(1+x)^2$

$$\left( \sum_{k=1}^n a_k b_k \right)^2 \leq \left( \sum_{k=1}^n a_k^2 \right) \left( \sum_{k=1}^n b_k^2 \right)$$

aaa

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