Radix sort is a sorting algorithm that sorts the elements by first grouping the individual digits of the same place value. Then, sort the elements according to their increasing/decreasing order.
Suppose, we have an array of 8 elements. First, we will sort elements based on the value of the unit place. Then, we will sort elements based on the value of the tenth place. This process goes on until the last significant place.
| Best | Average | Worst | Memory | Stable |
|---|---|---|---|---|
| Yes |
Where:
-
$n$ = the number of elements to sort -
$k$ = the maximum key length (number of digit places) of the elements to sort -
$b$ = the base (for example, for the decimal system,$b$ is 10)
radixSort(array)
d <- maximum number of digits in the largest element
create d buckets of size 0-9
for i <- 0 to d
sort the elements according to ith place digits using countingSort
countingSort(array, d)
max <- find largest element among dth place elements
initialize count array with all zeros
for j <- 0 to size
find the total count of each unique digit in dth place of elements and
store the count at jth index in count array
for i <- 1 to max
find the cumulative sum and store it in count array itself
for j <- size down to 1
restore the elements to array
decrease count of each element restored by 1
# Python program for implementation of Radix Sort
# A function to do counting sort of arr[] according to
# the digit represented by exp.
def countingSort(arr, exp1):
n = len(arr)
# The output array elements that will have sorted arr
output = [0] * (n)
# initialize count array as 0
count = [0] * (10)
# Store count of occurrences in count[]
for i in range(0, n):
index = arr[i] // exp1
count[index % 10] += 1
# Change count[i] so that count[i] now contains actual
# position of this digit in output array
for i in range(1, 10):
count[i] += count[i - 1]
# Build the output array
i = n - 1
while i >= 0:
index = arr[i] // exp1
output[count[index % 10] - 1] = arr[i]
count[index % 10] -= 1
i -= 1
# Copying the output array to arr[],
# so that arr now contains sorted numbers
i = 0
for i in range(0, len(arr)):
arr[i] = output[i]
# Method to do Radix Sort
def radixSort(arr):
# Find the maximum number to know number of digits
max1 = max(arr)
# Do counting sort for every digit. Note that instead
# of passing digit number, exp is passed. exp is 10^i
# where i is current digit number
exp = 1
while max1 / exp >= 1:
countingSort(arr, exp)
exp *= 10
# Driver code
arr = [170, 45, 75, 90, 802, 24, 2, 66]
# Function Call
radixSort(arr)
for i in range(len(arr)):
print(arr[i],end=" ")// C++ implementation of Radix Sort
#include <iostream>
using namespace std;
// A utility function to get maximum value in arr[]
int getMax(int arr[], int n)
{
int mx = arr[0];
for (int i = 1; i < n; i++)
if (arr[i] > mx)
mx = arr[i];
return mx;
}
// A function to do counting sort of arr[] according to
// the digit represented by exp.
void countSort(int arr[], int n, int exp)
{
int output[n]; // output array
int i, count[10] = { 0 };
// Store count of occurrences in count[]
for (i = 0; i < n; i++)
count[(arr[i] / exp) % 10]++;
// Change count[i] so that count[i] now contains actual
// position of this digit in output[]
for (i = 1; i < 10; i++)
count[i] += count[i - 1];
// Build the output array
for (i = n - 1; i >= 0; i--) {
output[count[(arr[i] / exp) % 10] - 1] = arr[i];
count[(arr[i] / exp) % 10]--;
}
// Copy the output array to arr[], so that arr[] now
// contains sorted numbers according to current digit
for (i = 0; i < n; i++)
arr[i] = output[i];
}
// The main function to that sorts arr[] of size n using
// Radix Sort
void radixsort(int arr[], int n)
{
// Find the maximum number to know number of digits
int m = getMax(arr, n);
// Do counting sort for every digit. Note that instead
// of passing digit number, exp is passed. exp is 10^i
// where i is current digit number
for (int exp = 1; m / exp > 0; exp *= 10)
countSort(arr, n, exp);
}
// A utility function to print an array
void print(int arr[], int n)
{
for (int i = 0; i < n; i++)
cout << arr[i] << " ";
}
// Driver Code
int main()
{
int arr[] = { 170, 45, 75, 90, 802, 24, 2, 66 };
int n = sizeof(arr) / sizeof(arr[0]);
// Function Call
radixsort(arr, n);
print(arr, n);
return 0;
}
// C# implementation of Radix Sort
using System;
class GFG {
public static int getMax(int[] arr, int n)
{
int mx = arr[0];
for (int i = 1; i < n; i++)
if (arr[i] > mx)
mx = arr[i];
return mx;
}
// A function to do counting sort of arr[] according to
// the digit represented by exp.
public static void countSort(int[] arr, int n, int exp)
{
int[] output = new int[n]; // output array
int i;
int[] count = new int[10];
// initializing all elements of count to 0
for (i = 0; i < 10; i++)
count[i] = 0;
// Store count of occurrences in count[]
for (i = 0; i < n; i++)
count[(arr[i] / exp) % 10]++;
// Change count[i] so that count[i] now contains
// actual
// position of this digit in output[]
for (i = 1; i < 10; i++)
count[i] += count[i - 1];
// Build the output array
for (i = n - 1; i >= 0; i--) {
output[count[(arr[i] / exp) % 10] - 1] = arr[i];
count[(arr[i] / exp) % 10]--;
}
// Copy the output array to arr[], so that arr[] now
// contains sorted numbers according to current
// digit
for (i = 0; i < n; i++)
arr[i] = output[i];
}
// The main function to that sorts arr[] of size n using
// Radix Sort
public static void radixsort(int[] arr, int n)
{
// Find the maximum number to know number of digits
int m = getMax(arr, n);
// Do counting sort for every digit. Note that
// instead of passing digit number, exp is passed.
// exp is 10^i where i is current digit number
for (int exp = 1; m / exp > 0; exp *= 10)
countSort(arr, n, exp);
}
// A utility function to print an array
public static void print(int[] arr, int n)
{
for (int i = 0; i < n; i++)
Console.Write(arr[i] + " ");
}
// Driver Code
public static void Main()
{
int[] arr = { 170, 45, 75, 90, 802, 24, 2, 66 };
int n = arr.Length;
// Function Call
radixsort(arr, n);
print(arr, n);
}
}// Radix sort Java implementation
import java.io.*;
import java.util.*;
class Radix {
// A utility function to get maximum value in arr[]
static int getMax(int arr[], int n)
{
int mx = arr[0];
for (int i = 1; i < n; i++)
if (arr[i] > mx)
mx = arr[i];
return mx;
}
// A function to do counting sort of arr[] according to
// the digit represented by exp.
static void countSort(int arr[], int n, int exp)
{
int output[] = new int[n]; // output array
int i;
int count[] = new int[10];
Arrays.fill(count, 0);
// Store count of occurrences in count[]
for (i = 0; i < n; i++)
count[(arr[i] / exp) % 10]++;
// Change count[i] so that count[i] now contains
// actual position of this digit in output[]
for (i = 1; i < 10; i++)
count[i] += count[i - 1];
// Build the output array
for (i = n - 1; i >= 0; i--) {
output[count[(arr[i] / exp) % 10] - 1] = arr[i];
count[(arr[i] / exp) % 10]--;
}
// Copy the output array to arr[], so that arr[] now
// contains sorted numbers according to current
// digit
for (i = 0; i < n; i++)
arr[i] = output[i];
}
// The main function to that sorts arr[] of
// size n using Radix Sort
static void radixsort(int arr[], int n)
{
// Find the maximum number to know number of digits
int m = getMax(arr, n);
// Do counting sort for every digit. Note that
// instead of passing digit number, exp is passed.
// exp is 10^i where i is current digit number
for (int exp = 1; m / exp > 0; exp *= 10)
countSort(arr, n, exp);
}
// A utility function to print an array
static void print(int arr[], int n)
{
for (int i = 0; i < n; i++)
System.out.print(arr[i] + " ");
}
// Main driver method
public static void main(String[] args)
{
int arr[] = { 170, 45, 75, 90, 802, 24, 2, 66 };
int n = arr.length;
// Function Call
radixsort(arr, n);
print(arr, n);
}
}<script>
// Radix sort Javascript implementation
// A utility function to get maximum value in arr[]
function getMax(arr,n)
{
let mx = arr[0];
for (let i = 1; i < n; i++)
if (arr[i] > mx)
mx = arr[i];
return mx;
}
// A function to do counting sort of arr[] according to
// the digit represented by exp.
function countSort(arr,n,exp)
{
let output = new Array(n); // output array
let i;
let count = new Array(10);
for(let i=0;i<10;i++)
count[i]=0;
// Store count of occurrences in count[]
for (i = 0; i < n; i++)
count[Math.floor(arr[i] / exp) % 10]++;
// Change count[i] so that count[i] now contains
// actual position of this digit in output[]
for (i = 1; i < 10; i++)
count[i] += count[i - 1];
// Build the output array
for (i = n - 1; i >= 0; i--) {
output[count[Math.floor(arr[i] / exp) % 10] - 1] = arr[i];
count[Math.floor(arr[i] / exp) % 10]--;
}
// Copy the output array to arr[], so that arr[] now
// contains sorted numbers according to current digit
for (i = 0; i < n; i++)
arr[i] = output[i];
}
// The main function to that sorts arr[] of size n using
// Radix Sort
function radixsort(arr,n)
{
// Find the maximum number to know number of digits
let m = getMax(arr, n);
// Do counting sort for every digit. Note that
// instead of passing digit number, exp is passed.
// exp is 10^i where i is current digit number
for (let exp = 1; Math.floor(m / exp) > 0; exp *= 10)
countSort(arr, n, exp);
}
// A utility function to print an array
function print(arr,n)
{
for (let i = 0; i < n; i++)
document.write(arr[i] + " ");
}
/*Driver Code*/
let arr=[170, 45, 75, 90, 802, 24, 2, 66];
let n = arr.length;
// Function Call
radixsort(arr, n);
print(arr, n);
</script>Radix sort is implemented in:
- DC3 algorithm (Kärkkäinen-Sanders-Burkhardt) while making a suffix array.
- places where there are numbers in large ranges.