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Alternating subarray prefix.cpp
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Alternating subarray prefix.cpp
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/*
RAJAT SINGH
VIT VELLORE
*/
#include<bits/stdc++.h>
using namespace std;
#define ll long long
//#define max 706000
#define gc getchar_unlocked
#define pc putchar_unlocked
//inline void get(int *p){register int n=0,sign=1,a=gc();while(a<'0'||a>'9'){ if(a=='-'){sign=-1;a=gc();break;} a=gc();}while(a>='0' && a<='9'){n=(n<<1)+(n<<3)+a-'0';a=gc();}*p=n*sign;}
//inline void put(int n){char d[10];int i=0;if(n<0){pc('-');n=-n;}do{d[i++]=n%10+'0';n=n/10;}while(n);while(i)pc(d[--i]);pc('\n');}
#define sc(a) scanf("%d ",&a)
#define p(a) printf("%lld\n",a)
#define l(i,a) for(int i=0;i<a;i++)
#define re(j,a,b) for(int j=a;j<b;j++)
# define ll long long
#define modu 1000000007
ll modular_pow(ll int base, ll int exponent)
{
if(exponent==0)
return 1;
else if(exponent%2==0){
ll int res=modular_pow(base,exponent/2);
return (res*res );
}
else{
return (modular_pow(base,exponent-1) * base);
}
}
int gcd(int a,int b){
if(b==0)
return a;//gcd
else return gcd(b,a%b);
}
bool chek(int x){
return (x&&!(x&(x-1)));// power of 2
}
int onebits(int n){
return __builtin_popcount(n);//count number od set bits in a number
}
bool che(int x, int y){
// char a[1000];
// char b[1000];
set< int >v;
vector< int >vv;
int f=x;
while(f!=0){
// v.insert(v.begin(),f%10);
v.insert(f%10);
f/=10;
}
int u;
//for( u=0;u<v.size();u++)
//a[u]=v[u];
//a[u]='/0';
// printf("%s",a);
//v.clear();
f=y;
while(f!=0){
// vv.insert(vv.begin(),f%10);
v.insert(f%10);
// ss1.insert(f%10);
f/=10;
}
//if(v.size()!=vv.size())
//return false;
//else{
//for( u=0;u<v.size();u++){
if(v.size()>1)
return false;
return true;
//b[u]='/0';
// v.clear();
// vv.clear();}
//printf("%s %s\n",a,b);
//if(strcmp(a,b)==0) return true;
}
int a[100001];
int dp[100001];
int main(){
//freopen("input.txt","r",stdin);
int t;
cin>>t;
while(t--){
int n;
cin>>n;
l(i,n) dp[i]=0;
l(i,n)
cin>>a[i];
// dp[i]=0;}
for(int u=n-1;u>=0;u--){
if(u==n-1) dp[u]=1;
else{
if((a[u]>=0 && a[u+1]<0) ||(a[u]<0&& a[u+1]>=0))
dp[u]=dp[u+1]+1;
else dp[u]=1;
}
}
l(i,n) cout<<dp[i]<<" ";
printf("\n");
}
return 0;
}