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main.cpp
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/// Source : https://leetcode.com/problems/delete-nodes-and-return-forest/
/// Author : liuyubobobo
/// Time : 2019-07-06
#include <iostream>
#include <vector>
using namespace std;
/// Simulations
/// Time Complexity: O(|to_delete| * n)
/// Space Complexity: O(h)
/// Definition for a binary tree node.
struct TreeNode {
int val;
TreeNode *left;
TreeNode *right;
TreeNode(int x) : val(x), left(NULL), right(NULL) {}
};
class Solution {
public:
vector<TreeNode*> delNodes(TreeNode* root, vector<int>& to_delete) {
vector<TreeNode*> res = {root};
for(int e: to_delete)
res = delNodes(res, e);
return res;
}
private:
vector<TreeNode*> delNodes(vector<TreeNode*> v, int to_delete){
vector<TreeNode*> ret;
bool ok = false;
for(TreeNode* root: v)
if(ok || !delNode(root, NULL, -1, root, to_delete, ret))
ret.push_back(root);
else
ok = true;
return ret;
}
bool delNode(TreeNode* root, TreeNode* parent, int index, TreeNode* node, int to_delete,
vector<TreeNode*>& ret){
if(!node) return false;
if(node->val == to_delete){
if(node == root){
if(node->left) ret.push_back(node->left);
if(node->right) ret.push_back(node->right);
}
else{
if(index == 0) parent->left = NULL;
else parent->right = NULL;
ret.push_back(root);
if(node->left) ret.push_back(node->left);
if(node->right) ret.push_back(node->right);
}
return true;
}
if(delNode(root, node, 0, node->left, to_delete, ret))
return true;
return delNode(root, node, 1, node->right, to_delete, ret);
}
};
int main() {
TreeNode* root = new TreeNode(1);
root->left = new TreeNode(2);
root->right = new TreeNode(3);
root->left->left = new TreeNode(4);
root->left->right = new TreeNode(5);
root->right->left = new TreeNode(6);
root->right->right = new TreeNode(7);
vector<int> to_delete = {3, 5};
Solution().delNodes(root, to_delete);
return 0;
}