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回调是如何传递外部参数的?
The text was updated successfully, but these errors were encountered:
$foo = 'foo'; $bar = 'bar'; function() use($foo, $bar){ echo $foo, $bar;// foo bar }
http://php.net/manual/zh/functions.anonymous.php
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谢谢!很好使
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回调是如何传递外部参数的?
The text was updated successfully, but these errors were encountered: