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solution.py
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assignments = []
rows = 'ABCDEFGHI'
cols = '123456789'
def cross(a, b):
return [s+t for s in a for t in b]
boxes = cross(rows, cols)
row_units = [cross(r, cols) for r in rows]
column_units = [cross(rows, c) for c in cols]
square_units = [cross(rs, cs) for rs in ('ABC','DEF','GHI') for cs in ('123','456','789')]
diag_units = [[r+c for r,c in zip(rows,cols)], [r+c for r,c in zip(rows,cols[::-1])]]
unitlist = row_units + column_units + square_units + diag_units
units = dict((s, [u for u in unitlist if s in u]) for s in boxes)
peers = dict((s, set(sum(units[s],[]))-set([s])) for s in boxes)
def assign_value(values, box, value):
"""
Please use this function to update your values dictionary!
Assigns a value to a given box. If it updates the board record it.
"""
# Don't waste memory appending actions that don't actually change any values
if values[box] == value:
return values
values[box] = value
if len(value) == 1:
assignments.append(values.copy())
return values
def naked_twins(values):
"""Eliminate values using the naked twins strategy.
Args:
values(dict): a dictionary of the form {'box_name': '123456789', ...}
Returns:
the values dictionary with the naked twins eliminated from peers.
"""
box_with_two_values = [box for box in values.keys() if len(values[box]) == 2] # boxes with 2 digit values
twins = [(x,y) for x in box_with_two_values for y in peers[x] if values[x] == values[y] if x != y]
# Find peers of twins.
common = dict()
for(first, second) in twins:
common[first] = list(peers[first].intersection(peers[second])) # identify the common elements for the twins.
# Update the values.
for box, boxes_to_update in common.items():
for eachBox in boxes_to_update:
# if int(values[eachBox]) > 1:
digits = values[box]
for digit in digits:
values[eachBox] = values[eachBox].replace(digit, '')
return values
def grid_values(grid):
"""
Convert grid into a dict of {square: char} with '123456789' for empties.
Args:
grid(string) - A grid in string form.
Returns:
A grid in dictionary form
Keys: The boxes, e.g., 'A1'
Values: The value in each box, e.g., '8'. If the box has no value, then the value will be '123456789'.
"""
chars = []
digits = '123456789'
for c in grid:
if c in digits:
chars.append(c)
if c == '.':
chars.append(digits)
assert len(chars) == 81
return dict(zip(boxes, chars))
def display(values):
"""
Display the values as a 2-D grid.
Args:
values(dict): The sudoku in dictionary form
"""
width = 1+max(len(values[s]) for s in boxes)
line = '+'.join(['-'*(width*3)]*3)
for r in rows:
print(''.join(values[r+c].center(width)+('|' if c in '36' else '')
for c in cols))
if r in 'CF': print(line)
return
def eliminate(values):
solved_values = [box for box in values.keys() if len(values[box]) == 1]
for box in solved_values:
digit = values[box]
for peer in peers[box]:
values[peer] = values[peer].replace(digit,'')
return values
def only_choice(values):
for unit in unitlist:
for digit in '123456789':
dplaces = [box for box in unit if digit in values[box]]
if len(dplaces) == 1:
values[dplaces[0]] = digit
return values
def reduce_puzzle(values):
solved_values = [box for box in values.keys() if len(values[box]) == 1]
stalled = False
while not stalled:
solved_values_before = len([box for box in values.keys() if len(values[box]) == 1])
values = eliminate(values)
values = only_choice(values)
solved_values_after = len([box for box in values.keys() if len(values[box]) == 1])
stalled = solved_values_before == solved_values_after
if len([box for box in values.keys() if len(values[box]) == 0]):
return False
return values
def search(values):
"Using depth-first search and propagation, try all possible values."
# First, reduce the puzzle using the previous function
values = reduce_puzzle(values)
if values is False:
return False ## Failed earlier
if all(len(values[s]) == 1 for s in boxes):
return values ## Solved!
# Choose one of the unfilled squares with the fewest possibilities
n,s = min((len(values[s]), s) for s in boxes if len(values[s]) > 1)
# Now use recurrence to solve each one of the resulting sudokus, and
for value in values[s]:
new_sudoku = values.copy()
new_sudoku[s] = value
attempt = search(new_sudoku)
if attempt:
return attempt
def solve(grid):
"""
Find the solution to a Sudoku grid.
Args:
grid(string): a string representing a sudoku grid.
Example: '2.............62....1....7...6..8...3...9...7...6..4...4....8....52.............3'
Returns:
The dictionary representation of the final sudoku grid. False if no solution exists.
"""
return search(grid_values(grid))
def solve2(values):
return search(values)
if __name__ == '__main__':
diag_sudoku_grid = '2.............62....1....7...6..8...3...9...7...6..4...4....8....52.............3'
diag_sudoku_dict = {"G7": "1234568", "G6": "9", "G5": "35678", "G4": "23678", "G3":
"245678", "G2": "123568", "G1": "1234678", "G9": "12345678", "G8":
"1234567", "C9": "13456", "C8": "13456", "C3": "4678", "C2": "68",
"C1": "4678", "C7": "13456", "C6": "368", "C5": "2", "A4": "5", "A9":
"2346", "A8": "2346", "F1": "123689", "F2": "7", "F3": "25689", "F4":
"23468", "F5": "1345689", "F6": "23568", "F7": "1234568", "F8":
"1234569", "F9": "1234568", "B4": "46", "B5": "46", "B6": "1", "B7":
"7", "E9": "12345678", "B1": "5", "B2": "2", "B3": "3", "C4": "9",
"B8": "8", "B9": "9", "I9": "1235678", "I8": "123567", "I1": "123678",
"I3": "25678", "I2": "123568", "I5": "35678", "I4": "23678", "I7":
"9", "I6": "4", "A1": "2468", "A3": "1", "A2": "9", "A5": "3468",
"E8": "12345679", "A7": "2346", "A6": "7", "E5": "13456789", "E4":
"234678", "E7": "1234568", "E6": "23568", "E1": "123689", "E3":
"25689", "E2": "123568", "H8": "234567", "H9": "2345678", "H2":
"23568", "H3": "2456789", "H1": "2346789", "H6": "23568", "H7":
"234568", "H4": "1", "H5": "35678", "D8": "1235679", "D9": "1235678",
"D6": "23568", "D7": "123568", "D4": "23678", "D5": "1356789", "D2":
"4", "D3": "25689", "D1": "123689"}
display(solve2(diag_sudoku_dict))
display(solve(diag_sudoku_grid))
try:
from visualize import visualize_assignments
visualize_assignments(assignments)
except SystemExit:
pass
except:
print('We could not visualize your board due to a pygame issue. Not a problem! It is not a requirement.')