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Unable to choose kernel #12160
Comments
thanks for filling this issue. |
Oh I think you are right. |
@DonJayamanne But the stable version has a bug reported in #11938. To prevent the duplicated intellisense I HAVE TO use the insider version according to #11938 (comment). My question is when to fix this bug in the stable version? |
it's very confusing when dealing with intellisense issues in this issue as they are completely unrelated. the issue #11938 had been fixed and it will be available in the next stable release. hence please wait till the next stable version |
Applies To
What happened?
2022.11.1003281132
but not on2022.11.1003291043
and2022.11.1003301027
.*.ipynb
file, the bottom left corner shows error message:Extension activation failed, run the 'Developer: Toggle Developer Tools' command for more information.
and the Developer Tools show this error message
Just like the Jupyter logs, it says that
TypeError: s.notebooks.createNotebookControllerDetectionTask is not a function
, which frankly doesn't come up in github search engine.Select Kernel
button is malfunctioning.The button in Jupyter version
2022.11.1003281132
works fine as below.Jupyter Show Output
command shows an error message: Command 'Jupyter: Show Output' resulted in an error (command 'jupyter.viewOutput' not found). So I paste the OUTPUT panel > Jupyter output in the issue'sJupyter logs
section.createNotebookControllerDetectionTask
but can't quite understand it; so maybe it's a vscode problem?VS Code Version
Version: 1.73.1 (user setup)
Commit: 6261075646f055b99068d3688932416f2346dd3b
Date: 2022-11-09T04:27:29.066Z
Electron: 19.0.17
Chromium: 102.0.5005.167
Node.js: 16.14.2
V8: 10.2.154.15-electron.0
OS: Windows_NT x64 10.0.19045
Sandboxed: No
Jupyter Extension Version
v2022.11.1003301027
Jupyter logs
logs
Coding Language and Runtime Version
Python v3.11.0
Language Extension Version (if applicable)
v2022.18.2
Anaconda Version (if applicable)
22.9.0
Running Jupyter locally or remotely?
Local
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