SQL Schema
Create table If Not Exists Products (product_id int, store1 int, store2 int, store3 int);
Truncate table Products;
insert into Products (product_id, store1, store2, store3) values ('0', '95', '100', '105');
insert into Products (product_id, store1, store2, store3) values ('1', '70', NULL, '80')Table: Products
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| product_id | int |
| store1 | int |
| store2 | int |
| store3 | int |
+-------------+---------+
product_id is the primary key for this table.
Each row in this table indicates the product's price in 3 different stores: store1, store2, and store3.
If the product is not available in a store, the price will be null in that store's column.
Write an SQL query to rearrange the Products table so that each row has (product_id, store, price). If a product is not available in a store, do not include a row with that product_id and store combination in the result table.
Return the result table in any order.
The query result format is in the following example.
Example 1:
Input:
Products table:
+------------+--------+--------+--------+
| product_id | store1 | store2 | store3 |
+------------+--------+--------+--------+
| 0 | 95 | 100 | 105 |
| 1 | 70 | null | 80 |
+------------+--------+--------+--------+
Output:
+------------+--------+-------+
| product_id | store | price |
+------------+--------+-------+
| 0 | store1 | 95 |
| 0 | store2 | 100 |
| 0 | store3 | 105 |
| 1 | store1 | 70 |
| 1 | store3 | 80 |
+------------+--------+-------+
Explanation:
Product 0 is available in all three stores with prices 95, 100, and 105 respectively.
Product 1 is available in store1 with price 70 and store3 with price 80. The product is not available in store2.
Solution
select product_id,"store1" as store, store1 as price from Products where store1 is NOT NULL
union
select product_id,"store2" as store, store2 as price from Products where store2 is NOT NULL
union
select product_id,"store3" as store, store3 as price from Products where store3 is NOT NULL