how to make all locust users wait after executing on_start method ?

[naga-sagar]

Hi,

I have a use case where login will happen slowly (i.e. on_start will have login function) and hatchrate will be at 2000 but no of users simulated will be close to 70,000.

After login, I need all the users to wait and hit the next api call at exact same time so that the load will be at 70,000. How do i achieve it ?

Thanks
Sagar

[aldenpeterson-wf]

It sounds like you want to use a normal python script and not use Locust since you aren't really doing the type of load testing that Locust was designed for.

[naga-sagar]

Thanks for your prompt reply.

Let me explain my scenario in detail. There is an application where users login initially and since this login service can't handle too many request at once, we do slow ramp by giving the hatch rate. Once the ramp up is done, we want to bombard with many requests at once.

here is the sample code we are using:
class DesktopTaskSet(TaskSet):
tasks = {task1: 10}
def on_start(self):
self.client.get(master_url)
class PerfTest(HttpLocust):
task_set = DesktopTaskSet

once i start locust, i give users as 70000 with hatch rate of 2000. Here we wanted the all the users(70000) to complete on_start (at hatch rate of 2000) to be completed and later the task1 should get all the requests(70000 task1) at once. Please let me know how it be achieved. Once again, thanks for your help.

Thanks
Sagar

[daluu]

I came across this thread earlier researching locust, this comment on use of semaphores might be what you need: #59 (comment)

[cyberw]

Closing this due to lack of activity. I hope you solved your issue, otherwise try slack!