Given a linked list, remove the nth node from the end of list and return its head.
For example,
Given linked list: 1->2->3->4->5, and n = 2.
After removing the second node from the end, the linked list becomes 1->2->3->5.
Note:
- Given n will always be valid. 不存在链的长度<n的情况
- Try to do this in one pass.
- 获取倒数第n个节点的父节点d
- 再根据父节点d是否为head节点,选取不同的删除方式。