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Copy pathSentences 11.10.sen
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Sentences 11.10.sen
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7.1.1.18681wnds:Windows 76.1SntFC1396179541891D1396179799728D1396179813486C1396180465816D1396180475553D1396180572470S1691420~@x (/y (x = y) $ x = d)
; Do you see what this is trying to say about the
; world? (Notice the names.) You can't express
; that in the blocks language. Negate the whole
; sentence.@x @y (((Cube(x) & Cube(y)) & (x # y)) $ /z Between(z,x, y))
; Now this sentence tries to make a reasonable
; claim. Why is it false? Play the game and see.
; Then fix it so it says what was intended.@x (Between(x, d, c) $ x = b)@x (/y Between(x, y, c) $ x = b)@x (/y Between(x, y, c) $ ~Large(x))@x (/y /z Between(x, y, z) $ ~Large(x))@x (/y /z Between(x, y, z) $ Tet(x))@x (~/y LeftOf(y, x) $ x = a)@x ((~/y LeftOf(y, x) & ~/y FrontOf(y, x)) $ x = a)@x (/y /z (Between(x, y, z) & Tet(y) & Tet(z))
$ x = e)@x (/y /z (Between(x, y, z) & Cube(y) & Cube(z))
$ x = b)@y (/x /z (Between(x, y, z) & x = b) $
(y = a | y = c))@x @y ((Tet(x) & Small(x) & Tet(y) & Small(y))
$ x = y)
; Do you see what this says?@x @y ((Dodec(x) & Small(x) & Dodec(y) & Small(y))
$ x = y)
; If you understood the last one, you see why this is
; true as well.@x (Dodec(x) $ x = b)
; This may look like a dumb thing to say, but make
; sure you understand it. Why is it true?@x (Dodec(x) % x = b)
; And do you see why this is false? Under what
; circumstances would it be true?@x ((Tet(x) & Small(x)) % x = b)
; This time, we got it right./y @x ((Tet(x) & Small(x)) % x = y)
; Compare this with the previous sentence. Do
; you understand what it says? Play the game
; a couple times, committed to both true and false./y @x ((Cube(x) & Small(x)) % x = y)
; Play the game here, too. Do you see why you can't
; win when committed to true?/y @x ((Tet(x) & Large(x)) % x = y)
; In this slot, write a sentence that says there's
; exactly one large tetrahedron. Pattern it on
; sentence 18.s=313193;