Better fix for issue #30.

R/RowFactor.R

@@ -57,6 +57,7 @@ RowFactor <- function(x, name = deparse(expr), levelnames=levels(x),
             else insert <- nopagebreak
             catname <- paste(insert, levelnames[i], sep="")
     	    test <- i  # Work around a bug in R 2.12.x!
+
     	    test <- call("labelSubset",
     	                 subset = call("==", call("as.integer", call("as.factor", expr)), i),
     	                 label = deparse(expr))

R/tabular.R

@@ -629,15 +629,21 @@ tabular.formula <- function(table, data=NULL, n, suppressLabels=0, ...) {
     if (missing(n) && inherits(data, "data.frame"))
     	n <- nrow(data)
 
-    # We need access to labelSubset() (and perhaps other functions)
-    # when evaluating a table expression. (Issue #30)
+    # We need access to labelSubset() (and perhaps other functions in future)
+    # when evaluating a table expression (issue #30), but we don't want
+    # to mask the user's copy.
 
-    withTableFns <- new.env(parent = if (is.environment(data)) data else environment(table))
-    withTableFns$labelSubset <- labelSubset
-    if (is.null(data))
+    parent <- if (is.environment(data)) data else environment(table)
+    if (!exists("labelSubset", envir = parent)) {
+      withTableFns <- new.env(parent = parent)
+      withTableFns$labelSubset <- labelSubset
+    } else
+      withTableFns <- parent
+
+    if (is.null(data) || is.environment(data))
     	data <- withTableFns
     else if (is.list(data))
-    	data <- list2env(data, parent=withTableFns)
+    	data <- list2env(data, parent = environment(table))
     else if (!is.environment(data))
     	stop("'data' must be a dataframe, list or environment")