loops_p2.py

# This function counts the number of integer factors for a 
# "given_number" variable, passed through the function’s parameters.
# The "count" return value includes the "given_number" itself as a 
# factor (n*1). 
def count_factors(given_number):
 
  # To include the "given_number" variable as a "factor", initialize
  # the "factor" variable with the value 1 (if the "factor" variable
  # were to start at 2, the "given_number" itself would be excluded). 
  factor = 1
  count = 1
 
  # This "if" block will run if the "given_number" equals 0.
  if given_number == 0:
    # If True, the return value will be 0 factors. 
    return 0
 
  # The while loop will run while the "factor" is still less than
  # the "given_number" variable.
  while factor < given_number:
    # This "if" block checks if the "given_number" can be divided by
    # the "factor" variable without leaving a remainder. The modulo
    # operator % is used to test for a remainder.
    if given_number % factor == 0:
      # If True, then the "factor" variable is added to the count of
      # the "given_number"’s integer factors.
      count += 1
    # When exiting the if block, increment the "factor" variable by 1
    # to divide the "given_number" variable by a new "factor" value
    # inside the while loop.
    factor += 1
 
  # When the interpreter exits either the while loop or the top if
  # block, it will return the value of the "count" variable.
  return count
 
print(count_factors(0)) # Count value will be 0
print(count_factors(3)) # Should count 2 factors (1x3)
print(count_factors(10)) # Should count 4 factors (1x10, 2x5)
print(count_factors(24)) # Should count 8 factors (1x24, 2x12, 3x8,
# and 4x6).