[Question] 'pyarmor-7 register' failed with HTTP Error 400

[Bajirak]

The following error occurred in the process of executing pyarmor register

Why did the error occur and what should I do to fix it?

COMMAND:
pyarmor-7 register pyarmor-regcode-1540.txt

ERROR:
`INFO PyArmor Version 8.0.21
INFO Python 3.8.13
INFO Read registration code file: pyarmor-regcode-1540.txt
INFO Start to activate this code
Traceback (most recent call last):
File "xxx/venv/lib/python3.8/site-packages/pyarmor/utils.py", line 1685, in _urlopen
return urlopen(*args, **kwargs)
File "/usr/lib/python3.8/urllib/request.py", line 222, in urlopen
return opener.open(url, data, timeout)
File "/usr/lib/python3.8/urllib/request.py", line 531, in open
response = meth(req, response)
File "/usr/lib/python3.8/urllib/request.py", line 640, in http_response
response = self.parent.error(
File "/usr/lib/python3.8/urllib/request.py", line 569, in error
return self._call_chain(*args)
File "/usr/lib/python3.8/urllib/request.py", line 502, in _call_chain
result = func(*args)
File "/usr/lib/python3.8/urllib/request.py", line 649, in http_error_default
raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 400: Bad Request

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
File "xxx/venv/bin/pyarmor-7", line 8, in
sys.exit(main_entry())
File "xxx/venv/lib/python3.8/site-packages/pyarmor/pyarmor.py", line 1612, in main_entry
main(sys.argv[1:])
File "xxx/venv/lib/python3.8/site-packages/pyarmor/pyarmor.py", line 1604, in main
args.func(args)
File "xxx/venv/lib/python3.8/site-packages/pyarmor/pyarmor.py", line 866, in _register
filename = activate_regcode(ucode)
File "xxx/venv/lib/python3.8/site-packages/pyarmor/register.py", line 74, in activate_regcode
res = _urlopen(reg_url % ucode, timeout=6.0)
File "xxx/venv/lib/python3.8/site-packages/pyarmor/utils.py", line 1689, in _urlopen
return urlopen(*args, **kwargs)
File "/usr/lib/python3.8/urllib/request.py", line 222, in urlopen
return opener.open(url, data, timeout)
File "/usr/lib/python3.8/urllib/request.py", line 531, in open
response = meth(req, response)
File "/usr/lib/python3.8/urllib/request.py", line 640, in http_response
response = self.parent.error(
File "/usr/lib/python3.8/urllib/request.py", line 569, in error
return self._call_chain(*args)
File "/usr/lib/python3.8/urllib/request.py", line 502, in _call_chain
result = func(*args)
File "/usr/lib/python3.8/urllib/request.py", line 649, in http_error_default
raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 503: Service Temporarily Unavailable`

ENVIROMENT:
python version : 3.8
register-key : About 2years ago purchased

[jondy]

Refer to #985 and #980

And it's better there is clear title.

[Bajirak]

@jondy

Thank you for your advice