Write a function f(N) that logs out numbers from 0 to N, but replacing:
- numbers divisible by 3 with the word "Fizz"
- numbers divisible by 5 with the word "Buzz"
- numbers divisible by 15 with the word "FizzBuzz"
- returns remainder of a division
%operator- eg:
7 % 3 = 1
Not the best solution performance-wise