% DATE-SEQ(1) % Clark Grubb % June 17, 2013
date-seq - print sequence of dates or times
date-seq [--format=FMT] [--weekdays=DAY[,DAY]...] YYYY[MM[DD[HH]]] YYYY[MM[DD[HH]]]
Generate a sequence of dates or times.
The command takes two arguments: the start date and the end date. The generated sequence is inclusive.
The format of the date arguments is YYYY[MM[DD[HH[MI[SS]]]]]. As little as the year or as much as the second can be specified. The end date must be the same length as the start date.
If the arguments have a YYYYMMDD format, the sequence will consist of days. If the arguments have a YYYYMMDDHH format, the sequence will consist of hours. Sequences of years, months, minutes, or seconds are also possible.
--format
: strftime style format string to control output.
--regex : a regular expression which can be used to filter the sequence. The regular expression should be written to apply to the YYYY[MM[DD[HH[MI[SS]]]]] format, not the output format specified by the --format flag.
--weekdays : comma separated list of weekdays. Dates for days outside the list are excluded.
Every Monday, Wednesday, and Friday in October 2012:
date-seq --weekdays=Mon,Wed,Fri 20121001 20121031Every fourth day starting October 1, 2012:
date-seq 20121001 20121101 | awk 'NR % 4 == 0'The second day of each month of 2012 in YYYY-MM-DD format:
date-seq --format='%F' --regex='.{6}02' 20120101 20121231The 30 most recent days in YYYYMMDD format:
date-seq 20100101 $(date +'%Y%m%d') | tail -30strftime (3), seq (1), grep (1), awk (1)