Regular keys break is_pressed on Mac

[mqw]

On my Mac keyboard.is_pressed('escape') works, keyboard.is_pressed('f') does not.

  File "/opt/homebrew/lib/python3.11/site-packages/keyboard/__init__.py", line 324, in key_to_scan_codes
    raise ValueError('Key {} is not mapped to any known key.'.format(repr(key)), e)
ValueError: ("Key 'f' is not mapped to any known key.", ValueError('Unrecognized character: f'))

Digging through code I have found that:

print(keyboard._os_keyboard.key_controller.key_map.non_layout_keys)
print(keyboard._os_keyboard.key_controller.key_map.layout_specific_keys)

prints

{36: 'enter', 48: 'tab', 49: 'space', 51: 'delete', 53: 'esc', 55: 'command', 56: 'shift', 57: 'caps lock', 58: 'alt', 59: 'ctrl', 60: 'right shift', 61: 'right option', 62: 'right ctrl', 63: 'ƒ', 64: 'f17', 72: 'volume up', 73: 'volume down', 74: 'mute', 79: 'f18', 80: 'f19', 90: 'f20', 96: 'f5', 97: 'f6', 98: 'f7', 99: 'f3', 100: 'f8', 101: 'f9', 103: 'f11', 105: 'f13', 106: 'f16', 107: 'f14', 109: 'f10', 111: 'f12', 113: 'f15', 114: 'help', 115: 'home', 116: 'page up', 117: 'forward delete', 118: 'f4', 119: 'end', 120: 'f2', 121: 'page down', 122: 'f1', 123: 'left', 124: 'right', 125: 'down', 126: 'up'}
{0: ('', ''), 1: ('', ''), 2: ('', ''), 3: ('', ''), 4: ('', ''), 5: ('', ''), 6: ('', ''), 7: ('', ''), 8: ('', ''), 9: ('', ''), 10: ('', ''), 11: ('', ''), 12: ('', ''), 13: ('', ''), 14: ('', ''), 15: ('', ''), 16: ('', ''), 17: ('', ''), 18: ('', ''), 19: ('', ''), 20: ('', ''), 21: ('', ''), 22: ('', ''), 23: ('', ''), 24: ('', ''), 25: ('', ''), 26: ('', ''), 27: ('', ''), 28: ('', ''), 29: ('', ''), 30: ('', ''), 31: ('', ''), 32: ('', ''), 33: ('', ''), 34: ('', ''), 35: ('', ''), 36: ('', ''), 37: ('', ''), 38: ('', ''), 39: ('', ''), 40: ('', ''), 41: ('', ''), 42: ('', ''), 43: ('', ''), 44: ('', ''), 45: ('', ''), 46: ('', ''), 47: ('', ''), 48: ('', ''), 49: ('', ''), 50: ('', ''), 51: ('', ''), 52: ('', ''), 53: ('', ''), 54: ('', ''), 55: ('', ''), 56: ('', ''), 57: ('', ''), 58: ('', ''), 59: ('', ''), 60: ('', ''), 61: ('', ''), 62: ('', ''), 63: ('', ''), 64: ('', ''), 65: ('', ''), 66: ('', ''), 67: ('', ''), 68: ('', ''), 69: ('', ''), 70: ('', ''), 71: ('', ''), 72: ('', ''), 73: ('', ''), 74: ('', ''), 75: ('', ''), 76: ('', ''), 77: ('', ''), 78: ('', ''), 79: ('', ''), 80: ('', ''), 81: ('', ''), 82: ('', ''), 83: ('', ''), 84: ('', ''), 85: ('', ''), 86: ('', ''), 87: ('', ''), 88: ('', ''), 89: ('', ''), 90: ('', ''), 91: ('', ''), 92: ('', ''), 93: ('', ''), 94: ('', ''), 95: ('', ''), 96: ('', ''), 97: ('', ''), 98: ('', ''), 99: ('', ''), 100: ('', ''), 101: ('', ''), 102: ('', ''), 103: ('', ''), 104: ('', ''), 105: ('', ''), 106: ('', ''), 107: ('', ''), 108: ('', ''), 109: ('', ''), 110: ('', ''), 111: ('', ''), 112: ('', ''), 113: ('', ''), 114: ('', ''), 115: ('', ''), 116: ('', ''), 117: ('', ''), 118: ('', ''), 119: ('', ''), 120: ('', ''), 121: ('', ''), 122: ('', ''), 123: ('', ''), 124: ('', ''), 125: ('', ''), 126: ('', ''), 127: ('', '')}

The latter dicts values are not set in KeyMap class __init__

for key_code in range(0, 128):
  non_shifted_char = UniChar4()
  shifted_char = UniChar4()
  keys_down = ctypes.c_uint32()
  char_count = UniCharCount()

I have tried just filling the constructor parameters, but it is not sufficient - it does prevent the error, but keyboard.is_pressed('f') still does not work.