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Combinations.swift
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Combinations.swift
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//===----------------------------------------------------------------------===//
//
// This source file is part of the Swift Algorithms open source project
//
// Copyright (c) 2020-2021 Apple Inc. and the Swift project authors
// Licensed under Apache License v2.0 with Runtime Library Exception
//
// See https://swift.org/LICENSE.txt for license information
//
//===----------------------------------------------------------------------===//
/// A collection wrapper that generates combinations of a base collection.
public struct CombinationsSequence<Base: Collection> {
/// The collection to iterate over for combinations.
@usableFromInline
internal let base: Base
@usableFromInline
internal let baseCount: Int
/// The range of accepted sizes of combinations.
///
/// - Note: This may be `nil` if the attempted range entirely exceeds the
/// upper bounds of the size of the `base` collection.
@usableFromInline
internal let kRange: Range<Int>?
/// Initializes a `CombinationsSequence` for all combinations of `base` of
/// size `k`.
///
/// - Parameters:
/// - base: The collection to iterate over for combinations.
/// - k: The expected size of each combination.
@inlinable
internal init(_ base: Base, k: Int) {
self.init(base, kRange: k...k)
}
/// Initializes a `CombinationsSequence` for all combinations of `base` of
/// sizes within a given range.
///
/// - Parameters:
/// - base: The collection to iterate over for combinations.
/// - kRange: The range of accepted sizes of combinations.
@inlinable
internal init<R: RangeExpression>(
_ base: Base, kRange: R
) where R.Bound == Int {
let range = kRange.relative(to: 0 ..< .max)
self.base = base
let baseCount = base.count
self.baseCount = baseCount
let upperBound = baseCount + 1
self.kRange = range.lowerBound < upperBound
? range.clamped(to: 0 ..< upperBound)
: nil
}
/// The total number of combinations.
@inlinable
public var count: Int {
guard let k = self.kRange else { return 0 }
let n = baseCount
if k == 0 ..< (n + 1) {
return 1 << n
}
func binomial(n: Int, k: Int) -> Int {
switch k {
case n, 0: return 1
case n...: return 0
case (n / 2 + 1)...: return binomial(n: n, k: n - k)
default: return n * binomial(n: n - 1, k: k - 1) / k
}
}
return k.map {
binomial(n: n, k: $0)
}.reduce(0, +)
}
/// The total number of combinations.
@inlinable
public var underestimatedCount: Int { count }
}
extension CombinationsSequence: Sequence {
/// The iterator for a `CombinationsSequence` instance.
public struct Iterator: IteratorProtocol {
@usableFromInline
internal let base: Base
/// The current range of accepted sizes of combinations.
///
/// - Note: The range is contracted until empty while iterating over
/// combinations of different sizes. When the range is empty, iteration is
/// finished.
@usableFromInline
internal var kRange: Range<Int>
/// Whether or not iteration is finished (`kRange` is empty)
@inlinable
internal var isFinished: Bool {
return kRange.isEmpty
}
@usableFromInline
internal var indexes: [Base.Index]
@inlinable
internal init(_ combinations: CombinationsSequence) {
self.base = combinations.base
self.kRange = combinations.kRange ?? 0..<0
self.indexes = Array(combinations.base.indices.prefix(kRange.lowerBound))
}
/// Advances the current indices to the next set of combinations. If
/// `indexes.count == 3` and `base.count == 5`, the indices advance like
/// this:
///
/// [0, 1, 2]
/// [0, 1, 3]
/// [0, 1, 4] *
/// // * `base.endIndex` reached in `indexes.last`
/// // Advance penultimate index and propagate that change
/// [0, 2, 3]
/// [0, 2, 4] *
/// [0, 3, 4] *
/// [1, 2, 3]
/// [1, 2, 4] *
/// [1, 3, 4] *
/// [2, 3, 4] *
/// // Can't advance without needing to go past `base.endIndex`,
/// // so the iteration is finished.
@inlinable
internal mutating func advance() {
/// Advances `kRange` by incrementing its `lowerBound` until the range is
/// empty, when iteration is finished.
func advanceKRange() {
if kRange.lowerBound < kRange.upperBound {
let advancedLowerBound = kRange.lowerBound + 1
kRange = advancedLowerBound ..< kRange.upperBound
indexes.removeAll(keepingCapacity: true)
indexes.append(contentsOf: base.indices.prefix(kRange.lowerBound))
}
}
guard !indexes.isEmpty else {
// Initial state for combinations of 0 elements is an empty array with
// `finished == false`. Even though no indexes are involved, advancing
// from that state means we are finished with iterating.
advanceKRange()
return
}
let i = indexes.count - 1
base.formIndex(after: &indexes[i])
if indexes[i] != base.endIndex { return }
var j = i
while indexes[i] == base.endIndex {
j -= 1
guard j >= 0 else {
// Finished iterating over combinations of this size.
advanceKRange()
return
}
base.formIndex(after: &indexes[j])
for k in indexes.indices[(j + 1)...] {
indexes[k] = base.index(after: indexes[k - 1])
if indexes[k] == base.endIndex {
break
}
}
}
}
@inlinable
public mutating func next() -> [Base.Element]? {
guard !isFinished else { return nil }
defer { advance() }
return indexes.map { i in base[i] }
}
}
@inlinable
public func makeIterator() -> Iterator {
Iterator(self)
}
}
extension CombinationsSequence: LazySequenceProtocol
where Base: LazySequenceProtocol {}
//===----------------------------------------------------------------------===//
// combinations(ofCount:)
//===----------------------------------------------------------------------===//
extension Collection {
/// Returns a collection of combinations of this collection's elements, with
/// each combination having the specified number of elements.
///
/// This example prints the different combinations of 1 and 2 from an array of
/// four colors:
///
/// let colors = ["fuchsia", "cyan", "mauve", "magenta"]
/// for combo in colors.combinations(ofCount: 1...2) {
/// print(combo.joined(separator: ", "))
/// }
/// // fuchsia
/// // cyan
/// // mauve
/// // magenta
/// // fuchsia, cyan
/// // fuchsia, mauve
/// // fuchsia, magenta
/// // cyan, mauve
/// // cyan, magenta
/// // mauve, magenta
///
/// The returned collection presents combinations in a consistent order, where
/// the indices in each combination are in ascending lexicographical order.
/// That is, in the example above, the combinations in order are the elements
/// at `[0]`, `[1]`, `[2]`, `[3]`, `[0, 1]`, `[0, 2]`, `[0, 3]`, `[1, 2]`,
/// `[1, 3]`, and finally `[2, 3]`.
///
/// This example prints _all_ the combinations (including an empty array and
/// the original collection) from an array of numbers:
///
/// let numbers = [10, 20, 30, 40]
/// for combo in numbers.combinations(ofCount: 0...) {
/// print(combo)
/// }
/// // []
/// // [10]
/// // [20]
/// // [30]
/// // [40]
/// // [10, 20]
/// // [10, 30]
/// // [10, 40]
/// // [20, 30]
/// // [20, 40]
/// // [30, 40]
/// // [10, 20, 30]
/// // [10, 20, 40]
/// // [10, 30, 40]
/// // [20, 30, 40]
/// // [10, 20, 30, 40]
///
/// If `kRange` is `0...0`, the resulting sequence has exactly one element, an
/// empty array. The given range is limited to `0...base.count`. If the
/// limited range is empty, the resulting sequence has no elements.
///
/// - Parameter kRange: The range of numbers of elements to include in each
/// combination.
///
/// - Complexity: O(1) for random-access base collections. O(*n*) where *n*
/// is the number of elements in the base collection, since
/// `CombinationsSequence` accesses the `count` of the base collection.
@inlinable
public func combinations<R: RangeExpression>(
ofCount kRange: R
) -> CombinationsSequence<Self> where R.Bound == Int {
CombinationsSequence(self, kRange: kRange)
}
/// Returns a collection of combinations of this collection's elements, with
/// each combination having the specified number of elements.
///
/// This example prints the different combinations of three from an array of
/// four colors:
///
/// let colors = ["fuchsia", "cyan", "mauve", "magenta"]
/// for combo in colors.combinations(ofCount: 3) {
/// print(combo.joined(separator: ", "))
/// }
/// // fuchsia, cyan, mauve
/// // fuchsia, cyan, magenta
/// // fuchsia, mauve, magenta
/// // cyan, mauve, magenta
///
/// The returned collection presents combinations in a consistent order, where
/// the indices in each combination are in ascending lexicographical order.
/// That is, in the example above, the combinations in order are the elements
/// at `[0, 1, 2]`, `[0, 1, 3]`, `[0, 2, 3]`, and finally `[1, 2, 3]`.
///
/// If `k` is zero, the resulting sequence has exactly one element, an empty
/// array. If `k` is greater than the number of elements in this sequence,
/// the resulting sequence has no elements.
///
/// - Parameter k: The number of elements to include in each combination.
///
/// - Complexity: O(1) for random-access base collections. O(*n*) where *n*
/// is the number of elements in the base collection, since
/// `CombinationsSequence` accesses the `count` of the base collection.
@inlinable
public func combinations(ofCount k: Int) -> CombinationsSequence<Self> {
precondition(k >= 0, "Can't have combinations with a negative number of elements.")
return CombinationsSequence(self, k: k)
}
}