From c9c96294f1bb75800d2a9154d547c873012e491e Mon Sep 17 00:00:00 2001
From: alancqueiroz <67958316+alancqueiroz@users.noreply.github.com>
Date: Wed, 21 Oct 2020 11:19:20 -0300
Subject: [PATCH] fix: pass both tree parent nodes and children nodes when
 exporting

Fix export all data to excel with treeview bug. Example: http://plnkr.co/edit/hFPAO6W3EW8nlzt2

fix #7127, fix #6819
---
 packages/exporter/src/js/exporter.js | 16 ++++++----------
 1 file changed, 6 insertions(+), 10 deletions(-)

diff --git a/packages/exporter/src/js/exporter.js b/packages/exporter/src/js/exporter.js
index edccf756f4..9e704298a8 100755
--- a/packages/exporter/src/js/exporter.js
+++ b/packages/exporter/src/js/exporter.js
@@ -952,21 +952,17 @@
          * recurse down into the children to get to the raw data element
          * which is a row without children (a leaf).
          * @param {Node} aNode the tree node on the grid
-         * @returns {Array} an array of leaf nodes
+         * @returns {Array} an array with all child nodes from aNode
          */
         getRowsFromNode: function(aNode) {
-          var rows = [];
-          for (var i = 0; i<aNode.children.length; i++) {
-            if (aNode.children[i].children && aNode.children[i].children.length === 0) {
-              rows.push(aNode.children[i]);
-            } else {
-              var nodeRows = this.getRowsFromNode(aNode.children[i]);
-              rows = rows.concat(nodeRows);
-            }
+          var rows = [aNode];
+          if (aNode.children && aNode.children.length > 0) {
+              for (var i = 0; i < aNode.children.length; i++) {
+                  rows = rows.concat(this.getRowsFromNode(aNode.children[i]));
+              }
           }
           return rows;
         },
-
         /**
          * @ngdoc function
          * @name getDataSorted