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476. Number Complement.md

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15 lines (15 loc) · 460 Bytes

思路

先将num的bit全部翻转,再看num有多少前导0,然后用一个合适的mask对之前的翻转结果进行与操作即可。

C++

class Solution {
public:
    int findComplement(int num) {
        if(num == 0) return 1;
        int i, res = ~num, mask=0xffffffff;
        while(mask & num) mask <<= 1;
        return res & ~mask;
    }
};