kmeans_for_anchors.py

#-------------------------------------------------------------------------------------------------#
#   kmeans虽然会对数据集中的框进行聚类，但是很多数据集由于框的大小相近，聚类出来的9个框相差不大，
#   这样的框反而不利于模型的训练。因为不同的特征层适合不同大小的先验框，越浅的特征层适合越大的先验框
#   原始网络的先验框已经按大中小比例分配好了，不进行聚类也会有非常好的效果。
#-------------------------------------------------------------------------------------------------#
import glob
import xml.etree.ElementTree as ET

import numpy as np

def cas_iou(box,cluster):
    x = np.minimum(cluster[:,0],box[0])
    y = np.minimum(cluster[:,1],box[1])

    intersection = x * y
    area1 = box[0] * box[1]

    area2 = cluster[:,0] * cluster[:,1]
    iou = intersection / (area1 + area2 -intersection)

    return iou

def avg_iou(box,cluster):
    return np.mean([np.max(cas_iou(box[i],cluster)) for i in range(box.shape[0])])

def kmeans(box,k):
    # 取出一共有多少框
    row = box.shape[0]
    
    # 每个框各个点的位置
    distance = np.empty((row,k))
    
    # 最后的聚类位置
    last_clu = np.zeros((row,))

    np.random.seed()

    # 随机选5个当聚类中心
    cluster = box[np.random.choice(row,k,replace = False)]
    # cluster = random.sample(row, k)
    while True:
        # 计算每一行距离五个点的iou情况。
        for i in range(row):
            distance[i] = 1 - cas_iou(box[i],cluster)
        
        # 取出最小点
        near = np.argmin(distance,axis=1)

        if (last_clu == near).all():
            break
        
        # 求每一个类的中位点
        for j in range(k):
            cluster[j] = np.median(
                box[near == j],axis=0)

        last_clu = near

    return cluster

def load_data(path):
    data = []
    # 对于每一个xml都寻找box
    for xml_file in glob.glob('{}/*xml'.format(path)):
        tree = ET.parse(xml_file)
        height = int(tree.findtext('./size/height'))
        width = int(tree.findtext('./size/width'))
        if height<=0 or width<=0:
            continue
        
        # 对于每一个目标都获得它的宽高
        for obj in tree.iter('object'):
            xmin = int(float(obj.findtext('bndbox/xmin'))) / width
            ymin = int(float(obj.findtext('bndbox/ymin'))) / height
            xmax = int(float(obj.findtext('bndbox/xmax'))) / width
            ymax = int(float(obj.findtext('bndbox/ymax'))) / height

            xmin = np.float64(xmin)
            ymin = np.float64(ymin)
            xmax = np.float64(xmax)
            ymax = np.float64(ymax)
            # 得到宽高
            data.append([xmax-xmin,ymax-ymin])
    return np.array(data)


if __name__ == '__main__':
    # 运行该程序会计算'./VOCdevkit/VOC2007/Annotations'的xml
    # 会生成yolo_anchors.txt
    SIZE = 416
    anchors_num = 9
    # 载入数据集，可以使用VOC的xml
    path = r'./VOCdevkit/VOC2007/Annotations'
    
    # 载入所有的xml
    # 存储格式为转化为比例后的width,height
    data = load_data(path)
    
    # 使用k聚类算法
    out = kmeans(data,anchors_num)
    out = out[np.argsort(out[:,0])]
    print('acc:{:.2f}%'.format(avg_iou(data,out) * 100))
    print(out*SIZE)
    data = out*SIZE
    f = open("yolo_anchors.txt", 'w')
    row = np.shape(data)[0]
    for i in range(row):
        if i == 0:
            x_y = "%d,%d" % (data[i][0], data[i][1])
        else:
            x_y = ", %d,%d" % (data[i][0], data[i][1])
        f.write(x_y)
    f.close()