While loop within kernel fails if there are two conditions

[mawolf2023]

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Describe the bug

If you use a while loop inside a kernel with two conditions, the code fails and produces the following error.

python: /usr/local/llvm/include/llvm/Support/Casting.h:579: decltype(auto) llvm::cast(From*) [with To = mlir::arith::CmpIOp; From = mlir::Operation]: Assertion `isa(Val) && "cast() argument of incompatible type!"' failed.
Aborted (core dumped)

Steps to reproduce the bug

import cudaq

@cudaq.kernel
def test():
    reg = cudaq.qvector(5)

    y=1
    x=0
    while x < 4 and y==1:
        h(reg)
        x+=1

print(cudaq.sample(test))

Expected behavior

Expect the while loop to execute with the given logic.

Is this a regression? If it is, put the last known working version (or commit) here.

Not a regression

Environment

• CUDA-Q version: CUDA-Q Version 0.9.1 (https://github.com/NVIDIA/cuda-quantum a3ab722)
• Python version:
• C++ compiler:
• Operating system:

Suggestions

No response

[schweitzpgi]

I tried this on my machine and didn't repro the issue. The code generated is the correct short-circuit condition and while loop.

    cc.loop while {
      %3 = cc.load %2 : !cc.ptr<i64>
      %4 = arith.cmpi slt, %3, %c4_i64 : i64
      %5 = arith.cmpi eq, %4, %false : i1
      %6 = cc.if(%5) -> i1 {
        cc.continue %false : i1
      } else {
        %7 = cc.load %1 : !cc.ptr<i64>
        %8 = arith.cmpi eq, %7, %c1_i64 : i64
        cc.continue %8 : i1
      }
      cc.condition %6
    } do {

[bebora]

I can reproduce the issue while using docker images cu12-0.9.1 (stable) and cu12-latest (nightly).
The error can be bypassed by rewriting the loop condition, the following is equivalent but arguably a bit uglier:

-while x < 4 and y==1:
+while (x < 4) * (y==1):