Easy
https://leetcode.com/problems/single-number/submissions/
Given a non-empty array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
Example 1:
Input: [2,2,1]
Output: 1
Example 2:
Input: [4,1,2,1,2]
Output: 4
/**
* @param {number[]} nums
* @return {number}
*/
var singleNumber = function(nums) {
let reg = 0
for(let i = 0; i < nums.length; i ++) {
reg = reg ^ nums[i]
}
return reg
};