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The correct result should be $-1$, because for negative integer $s$ one would have $$\zeta(-n,a)=-\frac{B_{n+1}(a)}{n+1}$$
[Wikipedia]
For example Mathematica gives the correct result:
The current implementation of the generalized zeta function$\zeta(s,z)$ suffers from an imprecision for large negative $s$ :
The correct result should be$-1$ , because for negative integer $s$ one would have
$$\zeta(-n,a)=-\frac{B_{n+1}(a)}{n+1}$$
[Wikipedia]
For example
Mathematica
gives the correct result:The text was updated successfully, but these errors were encountered: