When IJULIA_NODEFAULTKERNEL is defined, exe is not.

[jmuchovej]

👋 I've run into an error while trying to build a container for a project I'm working on. We were trying to sidestep the default Julia kernel for a custom one, but it seems that exe is defined in kspec which is only loaded if IJULIA_NODEFAULTKERNEL is undefined.

Is this an intentional error?

IJulia.jl/deps/build.jl

Lines 3 to 7 in 537ee79

	if !haskey(ENV, "IJULIA_NODEFAULTKERNEL")
	# Install Jupyter kernel-spec file.
	include("kspec.jl")
	kernelpath = installkernel("Julia", "--project=@.")
	end

IJulia.jl/deps/build.jl

Line 18 in 537ee79

condajupyter = normpath(Conda.SCRIPTDIR, exe("jupyter"))

ERROR: Error building `IJulia`: 
#0 49.27 ERROR: LoadError: UndefVarError: exe not defined
#0 49.27 Stacktrace:
#0 49.27  [1] top-level scope
#0 49.27    @ ~/.julia/packages/IJulia/AQu2H/deps/build.jl:18
#0 49.27  [2] include(fname::String)
#0 49.27    @ Base.MainInclude ./client.jl:476
#0 49.27  [3] top-level scope
#0 49.27    @ none:5
#0 49.27 in expression starting at /home/vscode/.julia/packages/IJulia/AQu2H/deps/build.jl:18

[stevengj]

Looks like a bug, should be fixed in #1079.