We are given the head node root
of a binary tree, where additionally every node's value is either a 0 or a 1.
Return the same tree where every subtree (of the given tree) not containing a 1 has been removed.
(Recall that the subtree of a node X is X, plus every node that is a descendant of X.)
Input: [1,null,0,0,1]
Output: [1,null,0,null,1]
Explanation:
Only the red nodes satisfy the property "every subtree not containing a 1".
The diagram on the right represents the answer.
Input: [1,0,1,0,0,0,1]
Output: [1,null,1,null,1]
Input: [1,1,0,1,1,0,1,0]
Output: [1,1,0,1,1,null,1]
- The binary tree will have at most
100 nodes
. - The value of each node will only be
0
or1
.
-
java
- mine
Runtime: 0 ms, faster than 100.00% of Java
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ class Solution { public TreeNode pruneTree(TreeNode node) { if(node == null){ return node; } node.left = pruneTree(node.left); node.right = pruneTree(node.right); if(node.val == 0 && node.left == null && node.right == null){ node = null; } return node; } }
- mine